i want to write code for a question
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c=0.1(x-y)
x=4:0.01:12
y=sqrt(c/2)
i have to find the value of x for which c=.0038416
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Accepted Answer
Ameer Hamza
on 27 Sep 2020
Edited: Ameer Hamza
on 27 Sep 2020
Although this equation is linear is x, and you can write the equation of x. For a general case, you can use fsolve()
c = 0.0038416;
f = @(x) c - 0.1*(x-sqrt(c/2));
x = fsolve(f, 0);
If you have the symbolic toolbox
syms x
c = 0.0038416;
eq = c == 0.1*(x-sqrt(c/2));
x = double(solve(eq))
2 Comments
Ameer Hamza
on 27 Sep 2020
Thanks for pointing out. OP kept changing the question initially, so I forgot to make the change in the symbolic part.
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