Converting two decimal numbers into binary, concatenating the resulting 8 bit integers to get 16 bit signed integer and converting to signed float (IMU)

10 views (last 30 days)
So I have this 6DOF IMU that spits out data packets as follows:
sensorData = [85 13 109 85 12 147 12 0 156 0 71 255 229 10 144 252];
The acceleration in x axis for example, would be found by converting 12 and 147 to 8 bit binary numbers, concatenating them to get signed 16 bit binary number and converting them to signed floating point number.
I am not sure how to properly write the code to do the job. Here's my code for example, which doesn't work as expected:
sensorData = read(characteristic(b, "FF06", "FF08"));
z(i,1) = (typecast(uint16(bin2dec(strcat(dec2bin(sensorData(5),8), dec2bin(sensorData(6),8)))),'int16'))/SFacc; %SFacc = 8192 LSB/ms^-2
Am I doing something wrong? The values I receive are not what I am expecting.

Accepted Answer

Walter Roberson
Walter Roberson on 23 Nov 2019
double( swapbytes(typecast(uint8(sensorData), 'int16')) ) / SFacc
  4 Comments

Sign in to comment.

More Answers (0)

Tags

Products


Release

R2019b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!