can i make a loop for mentioned equation?

1 view (last 30 days)
Mamad Mamadi
Mamad Mamadi on 16 Nov 2019
Commented: Mamad Mamadi on 22 Nov 2019
hi everybody;
i want to find the value of (Pb_dis) from below equation and then make a loop to put (Pb_dis) value that i found from equation to (Pb1dis) to find (Pb_dis1) and to put the value of (Pb_dis1) to (Pb1dis) again to find (Pb_dis2) and so on . thank you very much i really appreciate it if you help me,
initial Pb1dis =3600 w
this is the equation:
Pb_dis= (Pb1dis*(1-sigma))-((Ppv/nu_i)-PL);
  3 Comments
Mamad Mamadi
Mamad Mamadi on 16 Nov 2019
Thank you for your answer and spending your time ,
I share the entire equation with values. really appriciate it if you help me to solve this eq.
the original equation are:
Pb(t)= (Pb(t-1)*(1-sigma))-((Ppv(t)/nu_i)-PL(t)); %for li-ion battery discharging
Pb(t)= (Pb(t-1)*(1-sigma))+(Ppv(t)-(PL(t)/nu_i))*nu_b; %for li-ion battery Charging
Pb(t-1)= 3600 %SOC at the begining (Wh) >>watt hour
%Ppv(t) = 123.3 %Enegy of PV(photovoltaic ) (Wh)
%PL(t) = 60 %Load Demand (Wh)
sigma = 2 %Self_Discharge factor
nu_i = 0.9 %inverter effeciency
nu_b= 0.95 %battery effeciency
t=time
Mamad Mamadi
Mamad Mamadi on 22 Nov 2019
Please I need your help. I appriciate it if you can help me thanks.

Sign in to comment.

Answers (2)

JESUS DAVID ARIZA ROYETH
JESUS DAVID ARIZA ROYETH on 16 Nov 2019
It would be something like this :
Pb1dis =inf;
Pb_dis2=3600;
tol=0.0001;%tolerance
while abs(Pb_dis2-Pb_dis)>tol
Pb_dis=Pb1dis2;
Pb_dis2= (Pb1dis*(1-sigma))-((Ppv/nu_i)-PL);
end
disp(Pb_dis2)
  2 Comments
Mamad Mamadi
Mamad Mamadi on 16 Nov 2019
Thank you for your answer and spending your time ,
I share the entire equation with values. really appriciate it if you help me to solve this eq.
the original equation is:
Pb(t)= (Pb(t-1)*(1-sigma))-((Ppv(t)/nu_i)-PL(t)); %for li-ion battery discharging
Pb(t)= (Pb(t-1)*(1-sigma))+(Ppv(t)-(PL(t)/nu_i))*nu_b; %for li-ion battery Charging
Pb(t-1)= 3600 %SOC at the begining (Wh) >>watt hour
%Ppv(t) = 123.3 %Enegy of PV(photovoltaic ) (Wh)
%PL(t) = 60 %Load Demand (Wh)
sigma = 2 %Self_Discharge factor
nu_i = 0.9 %inverter effeciency
nu_b= 0.95 %battery effeciency
t=time
Mamad Mamadi
Mamad Mamadi on 22 Nov 2019
could you please help me again. I used your codes but didnt work and shared it again completely. i really appricaite it if you help me. thanks

Sign in to comment.


wang sir
wang sir on 16 Nov 2019
HI,dude,I'm sorry,I can't answer you the question because I don't know how to use this software.But I wish we can make friends!

Categories

Find more on MATLAB in Help Center and File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!