Finding transpose of values.

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Silpa K
Silpa K on 6 Nov 2019
Commented: Walter Roberson on 6 Nov 2019
ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1:100
b=20
p=ts(i,:);
n= numel(p);
Z=mat2cell(p,diff([0:b:n-1,n]));
A=transpose(Z);
celldisp(A)
end
I want to find the transpose of Z values.I need the elements of Z in an array order.I used transpose,but not working.How can I get the elements of Z in an array form.Please help me.

Accepted Answer

Walter Roberson
Walter Roberson on 6 Nov 2019
ts = xlsread('ArrowHead_TRAIN.xlsx');
for i = 1 : size(ts,1)
b = 20;
p = ts(i,:);
n = numel(p);
Z = mat2cell(p, 1, diff([0:b:n-1,n]));
A = cellfun(@transpose, Z, 'uniform', 0);
celldisp(A)
end
  2 Comments
Walter Roberson
Walter Roberson on 6 Nov 2019
The result is row-wise if you do not do the transpose.

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