Can anyone help? I cannot figure out how to use a for loop to check elements in part of a matrix.
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Create a 5x4 matrix of random integers between -10 and 10 with the randi function. Write a for loop that will check each element in column 1 of the matrix. If that element is less than 0, change every element in that row to NaN.
I can make the actual matrix, but after that I don't know what comes next.
r=randi([-10,10],5,4)
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Accepted Answer
Stephen23
on 30 Oct 2019
Edited: Stephen23
on 30 Oct 2019
"I can make the actual matrix, but after that I don't know what comes next."
Your assignment tells you exactly what you need to do. Fill in the ??? yourself:
for k = 1:size(???) % loop over all row indices
if r(k,1)<??? % check if first column value is <0
r(k,:)=???; % change entire row to NaN
end
end
More Answers (2)
Bhaskar R
on 30 Oct 2019
Edited: Bhaskar R
on 30 Oct 2019
No need of for loop
r=randi([-10,10],5,4);
if any(r(:,1)<0)
r(1,:) = nan;
end
2 Comments
Stephen23
on 30 Oct 2019
The question states that "If that element is less than 0, change every element in that row to NaN", but this code always changes the first row to NaN, not the row/s where the negative values were found in the first column.
It is not clear how if is supposed to provide the requested behavior.
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