Change yticks using a stacked plot

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I am using the stackedplot function to display multiple series of data that share the same x axis. I would like to change the y ticks, but I can't figure out how to do it. In this case, I would like to make the y tick marks go by 4,000. So basically the y axis should have the following tick marks: 0, 4000, 8000, 12000. Attached is the figure. I can't seem to find a tick mark property in this graph and using
returns the following error:example stacked plot.png
Using xticks with stackedplot is not supported.

Accepted Answer

Artemio Soto Breceda
Artemio Soto Breceda on 23 Oct 2019
You should use the stackedplot with an output argument:
handle = stackedplot(rand(5)); % Plot 5 random vectors with 5 elements each
Then you can use the handle to change the properties of your figure:
handle.AxesProperties(1).YLimits = [0 12000]; % Changes the limits of the first plot
or in a for loop to change them all:
for i = 1:numel(handle.AxesProperties)
handle.AxesProperties(i).YLimits = [0 12000];
This does not quite control the ticks, instead it changes the limits of the axis, such as ylim([a b]) would do.
I do not think there is any property for stackedplot to do what you want, but this approach may suffice. Otherwise, I recommend you to use subplot and simply remove the xaxis of each subplot except for the last one.
for i = 1:5
h = subplot(5,1,i);
plot(rand(1,5)); % Plotting random numbers, here you put your data
if i < 5, h.XTick = [];end
box off
Then you can do what you want:
h.YTick = [0:4000:12000];
I think using subplot is a much better practice, because it gives you much more freedom.
Joe Vinciguerra
Joe Vinciguerra on 23 Oct 2019
Stackedplot is comparatively new, and lacks a lot of the fine-tune-ability available in other plot types. But I would expect to see this and similar shortcomings addressed in future releases.

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More Answers (1)

Adam Danz
Adam Danz on 19 Nov 2020
Edited: Adam Danz on 24 Nov 2020
You can get the axis handles in stackedplot using the undocumented NodeChildren property. Then set YTick.
h = stackedplot(1:20, rand(20,4)*1000+500);
ax = findobj(h.NodeChildren, 'Type','Axes');
set(ax, 'YTick', [600:300:1500], 'YLim', [500,1600])
To set ytick of a selected axis number n,
% set(ax(n), ...)
Eric Roden
Eric Roden on 12 Mar 2021
Yes, thank you, it took me a long time to find this, and am very happy I did!

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