for loop execution error

i had a for loop like this

for j=1:100
    for i=1:48
        F{j,1}(i,1)= some equations;
    end
end

this is running well when j (1:100)>i(1:48) and not running for j<i values like if

for j=1:30
    for i=1:48
        F{j,1}(i,1)= some equations;
    end
end

then its F cell having only 30 values for i=30th values . but I need 48 values when j=1:30 means F cell size should be {30,1} and each cell having (1*48) array.

and in another for loop,

for t=1:100
    G(t)=trapz(X(t),Y(t)); 
end

if at G(55) its values can not calculated due to X(55) or Y(55) have no values/data sufficient for its operation then how can I execute this for loop without the error because I need the array untill the error come or not come G(55) is needful for me before the error and want to continue the program .

Answer 1

[Sebastian Körner]

For your second problem try:

for t=1:100
   try
       G(t)=trapz(X(t),Y(t));
   catch
       continue;
   end
end

when the error occures at t=55 , you jump to the catch part and your loop continues with the next iterration

[MUKESH KUMAR]

thanks for your helps it working well but then after execution the G vector values from 56 to 100 is zero and size of G is (100,1) but i want it till G(55,1) only

[Sebastian Körner]

in this case simply replace the continue with break

for t=1:100
   try
       G(t)=trapz(X(t),Y(t));
   catch
       break;
   end
end