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How to Add Image Classes?

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Qvna Lhyvnav
Qvna Lhyvnav on 18 May 2019
Commented: Qvna Lhyvnav on 18 May 2019
I want to classify my image files into 4 classes, but I only get 0 and 1 with this code:
Target_Data = ones(1,Total_Images);
Target_Data(1:Total_Images/4) = 0;
How to add the other classes? Thank you.

Accepted Answer

Walter Roberson
Walter Roberson on 18 May 2019
Target_Data = repmat((1:4).', Total_Images/4, 1);
  7 Comments
Walter Roberson
Walter Roberson on 18 May 2019
Target_Data = repelem(1:4, Total_Images/4);
Qvna Lhyvnav
Qvna Lhyvnav on 18 May 2019
Done. Thank you for your help!

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More Answers (1)

KALYAN ACHARJYA
KALYAN ACHARJYA on 18 May 2019
Edited: KALYAN ACHARJYA on 18 May 2019
May be you are confusing with logical indexing, there is nothing related to classification of images
lets say Total_Images=8, that menas Target_Data= ones(1,8)
>> Target_Data=ones(1,Total_Images)
Target_Data =
1 1 1 1 1 1 1 1
in next line Total_Images/4=2, so the next line is Target_Data(1:2)=0
>> Target_Data(1:Total_Images/4)=0
Target_Data =
0 0 1 1 1 1 1 1
It is checking the 1 D array elements from 1 to 2 (Target_Data(1:2)) equal to zero or not, its false logic, therefore it is zero,
There for 1st and 2nd elements are 0 and rest are same as initial Taret__Data.
If you do following one, lets check all Target_Data elemets, wheather 0 or not, you may get all zero in resultant target elements.
>> Target_Data(1:8)=0
Target_Data =
0 0 0 0 0 0 0 0
I didnot find any clue to classes images based on these two statements, if you can, as you now undestand the code, do modification accordingly.
  1 Comment
Qvna Lhyvnav
Qvna Lhyvnav on 18 May 2019
Thank you for your reply. I understand, but I want to make four classes (60 files with each 15 files has different values). This code works for two classes.

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