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storing values in matrix using for loop

Asked by Darpan Verma on 13 Mar 2019
Latest activity Commented on by madhan ravi
on 13 Mar 2019
Accepted Answer by KSSV
Hi I want to store values in a [3x3] matrix but getting error. Any help would be appreciated
for i=1:3
answerA(i,1)=1*i
answerB(i,2)=2*i
answerC(i,3)=i
% tableA=[answerA answerB answer C]
end
table=[reshape(answerA,[],1) reshape(answerB,[],1) reshape(answerC,[],1)]
% table=[reshape(answerA,[],1)]
ERROR:
Error using horzcat
Dimensions of arrays being concatenated are not consistent.
Error in AllCurvesfit (line 80)
table=[reshape(answerA,[],1) reshape(answerB,[],1)]

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1 Answer

Answer by KSSV
on 13 Mar 2019
Edited by KSSV
on 13 Mar 2019
 Accepted Answer

answerA = zeros(3,1) ;
answerB = zeros(3,1) ;
answerC = zeros(3,1) ;
for i=1:3
answerA(i)=1*i ;
answerB(i)=2*i ;
answerC(i)=i ;
end
table=[answerA answerB answerC]
May be you wanted:
T = table(answerA, answerB, answerC)
The above can be achieved without loops also:
i = (1:3)' ;
A = [i 2*i i]

  1 Comment

Naming a variable table is a bad idea.

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