How to extract rows by date?

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Iris Li
Iris Li on 12 May 2018
Commented: Peter Perkins on 14 May 2018
say I have a table A
18-Dec-2015 42.3000 29.9000 7.3000
18-Dec-2015 37.3000 30.1000 13.4000
18-Dec-2015 39.1000 30.0300 6.5000
18-Dec-2015 42.3000 29.9000 7.3000
19-Dec-2015 37.3000 30.1000 13.4000
19-Dec-2015 39.1000 30.0300 6.5000
20-Dec-2015 42.3000 29.9000 7.3000
20-Dec-2015 39.1000 30.0300 6.5000
20-Dec-2015 37.3000 30.1000 13.4000
I have almost 3000 days to do. How could I use a loop to extract rows by time and do some calculation separately? Thanks in advance!!! I tried ismember and the following one but neither works.
for i = (:,1)
if A(i,1)=A(i+1,1)
C=A(i,:)
...
  2 Comments
Jan
Jan on 12 May 2018
It would be useful to post some code, which creates the example data or to attach the variable as MAT file. This would clarify, which format the "table" has exactly.
What is the purpose of "for i = (:,1)"? "Neither works" is less useful than posting the error message.
Iris Li
Iris Li on 12 May 2018
Sorry it's my bad for I'm not familiar with asking a question yet. What I need to do is to separate C and P for each day each maturity, and then merge by the common strike price And then do calculations later.
date = {'20160419';'20160419';'20160419';'20160419';'20160419';'20160419';'20160418';'20160418';'20160418';'20160418'};
cp_flag = {'C';'C';'C';'P';'P';'P';'C';'C';'P';'P'};
maturity = [2;2;1;2;2;1;2;1;2;1];
strike_price = [40;30;20;40;30;20;40;30;40;30];
mid_value = [0.021; 0.022; 0.033; NaN; 0.025;0.026;0.027; 0.028; 0.039; 0.041];
T = table(date,cp_flag,maturity,strike_price,mid_value)
T =
10×5 table
date cp_flag maturity strike_price mid_value
__________ _______ ________ ____________ _________
'20160419' 'C' 2 40 0.021
'20160419' 'C' 2 30 0.022
'20160419' 'C' 1 20 0.033
'20160419' 'P' 2 40 NaN
'20160419' 'P' 2 30 0.025
'20160419' 'P' 1 20 0.026
'20160418' 'C' 2 40 0.027
'20160418' 'C' 1 30 0.028
'20160418' 'P' 2 40 0.039
'20160418' 'P' 1 30 0.041
I need to get
T_new =
5×9 table
date cp_flag_A maturity_A strike_price_A cp_flag_B maturity_B strike_price_B mid_value_A mid_value_B
__________ _________ __________ ______________ _________ __________ ______________ ___________ ___________
'20160419' 'C' 2 40 'P' 2 40 0.021 NaN
'20160419' 'C' 2 30 'P' 2 30 0.022 0.025
'20160419' 'C' 1 20 'P' 1 20 0.033 0.026
'20160418' 'C' 2 40 'P' 2 40 0.027 0.039
'20160418' 'C' 1 30 'P' 1 30 0.028 0.041
find the corresponding strike price when the abs(mid_value_A - mid_value_B) is smallest.

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Accepted Answer

Akira Agata
Akira Agata on 12 May 2018
It's not clear what you want to do, but, as Star-san mentioned, retime function would be your help. Let me start assuming your table A has 4 columns and the 1st column is stored as datetime, like:
>> A
A =
9×4 table
Time Var1 Var2 Var3
__________ ____ _____ ____
2015/12/18 42.3 29.9 7.3
2015/12/18 37.3 30.1 13.4
2015/12/18 39.1 30.03 6.5
2015/12/18 42.3 29.9 7.3
2015/12/19 37.3 30.1 13.4
2015/12/19 39.1 30.03 6.5
2015/12/20 42.3 29.9 7.3
2015/12/20 39.1 30.03 6.5
2015/12/20 37.3 30.1 13.4
To use retime function, first you should convert your table into "timetable" by using table2timetable function.
>> A = table2timetable(A);
>> A
A =
9×3 timetable
Time Var1 Var2 Var3
__________ ____ _____ ____
2015/12/18 42.3 29.9 7.3
2015/12/18 37.3 30.1 13.4
2015/12/18 39.1 30.03 6.5
2015/12/18 42.3 29.9 7.3
2015/12/19 37.3 30.1 13.4
2015/12/19 39.1 30.03 6.5
2015/12/20 42.3 29.9 7.3
2015/12/20 39.1 30.03 6.5
2015/12/20 37.3 30.1 13.4
Now you can use retime function to do some calculation separately for each day. For example, you can calculate daily average for each variable (Var1~Var3) in 1 line, like:
>> retime(A,'daily','mean')
ans =
3×3 timetable
Time Var1 Var2 Var3
__________ ______ ______ ______
2015/12/18 40.25 29.983 8.625
2015/12/19 38.2 30.065 9.95
2015/12/20 39.567 30.01 9.0667
I hope my post somehow helps you !
  4 Comments
Iris Li
Iris Li on 14 May 2018
Thank you a thousand times!!!
Peter Perkins
Peter Perkins on 14 May 2018
Iris, you really want to turn Date into a datetime, not text, and turn cp_flag into categorical, not text. Your life will be much easier.

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More Answers (1)

Star Strider
Star Strider on 12 May 2018
I have no idea what you are doing, so I am guessing here.
If you have R2016b or later, see if the retime (link) function will help you do what you want.

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