Plot Circle In For Loop
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Kelly McGuire
on 27 Apr 2018
Commented: Kelly McGuire
on 30 Apr 2018
I have this code that is set up to animate a circle plot based on the circle's diameter. I am struggling with how to plot the circle based on the diameter in the for loop. I have one column vector of 1,667 columns. In each of those columns is the diameter (i.e. 1,667 diameters from data). I want to animate the circle changing based on those diameters. So, I need the plot in the for loop to go through, iterate through the columns, and update the plot, and but show that as an animation. I've attached my code. Please help with the plot portion of the code, thanks!
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Accepted Answer
Ameer Hamza
on 27 Apr 2018
Edited: Ameer Hamza
on 27 Apr 2018
@Kelly, As I answered on your previous question, that you need to fill the plot for circle yourself. If you are still not able to make that work then here is the complete code.
B = 10:10:1000; % test B vector. You will use your own B
animationWriter = VideoWriter('HSPtoHSPCircle');
open(animationWriter);
l = line();
l.XData = [];
l.YData = [];
xlim([-max(B) max(B)]);
ylim([-max(B) max(B)]);
theta = 0:pi/50:2*pi;
for i = 1:length(B)
% create data for circle plot or any other
% processing you want to do
xData = B(i)*cos(theta);
yData = B(i)*sin(theta);
l.XData = xData;
l.YData = yData;
frame = getframe(gcf);
writeVideo(animationWriter, frame);
end
close(animationWriter);
I created this animation using given code.
6 Comments
Ameer Hamza
on 30 Apr 2018
As far as changing the labels on X-axis is concerned, the following code can do it,
ax.XLim = [1 4]
ax.XTick = 1:4
ax.XTickLabel = {'residue 1', 'residue 2', 'residue 3', 'residue 4'}
As far as making an animation with moving line is concerned. It is quite different to this question. Here is an outline of how can you do it.
- Make a linear interpolation of edges between two rows of your data matrix.
- Instead of just drawing the rows of your matrix, also plot all the interpolated points. This way, the animation will look smooth.
If you still face a problem, you might want to start a new question, because the new problem is quite out of the scope for this question.
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