Simpson's Rule to find total work

If I'm given time=[0,#,#,#,#,#] and velocity=[#,#,#,#,#,#] and Force=[#,#,#,#,#,#], how could I use Simpson's rule to find the total work in this time? I know work is area under curve of Force vs distance, and I know distance/position is area under curve of velocity vs time.

So far I have this:

n=6
sum2=0
sum1=0
sumn=0
P(1)=0

for i=0:n
    if i==0
        sum0= v(i+1)
    elseif i==n
        sumn = v(i) %TA wrote v(i+1)?
    elseif mod(i,2)==1
        sum1=sum1 + v(i+1)
    elseif mod(i,2)==0
        sum2=sum2+v(i+1)
    end
    delt=(t(n)-t(1))/3
    area1=delt*(sum0 + sumn + 4*sum2 + 2*sum2)
    if i>1
    P(i)= P(i-1) +area1
    end
end

1) Not sure if I found the correct position values. Is it wrong to assume P(1)=0?

2)for total work, Would I repeat the same for loop, but now with Force and Position values?