how can i write if condition for an empty array?
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Following is the code:
clc
A=[333.3333 -333.3333 0;333.3333 666.6667 -333.3333;0 -333.3333 333.3333]
F=[0;0;10]
o=[]
%B=[1,o]
n1=input('Boundry Condition for N1')
n2=input('Boundry Condition for N2')
B=[n1,n2]
if n1==1 & n2==o;%1=fixed & o=free, but cant read this after running file
c=2
d=n
disp('Loop 1')
elseif n1==o & n2==1;
c=1
d=n-1
disp('Loop 2')
else n1==1 & n2==1;
c=2
d=n-1
disp('Loop 3')
end
AuxEqn=A(B,c:d)
AuxRHs=F(B)
A(B,:)=[];
A(:,B)=[]
F(B)=[]
U=inv(A)*F
R=AuxEqn*U
0 Comments
Accepted Answer
Walter Roberson
on 15 Nov 2017
You cannot compare [] to anything. Use isempty() to test for empty matrix.
4 Comments
Walter Roberson
on 17 Nov 2017
Edited: Walter Roberson
on 17 Nov 2017
if n1==1 && isempty(n2);
c=2
d=n
disp('Loop 1')
elseif isempty(n1) && n2==1
c=1
d=n-1
disp('Loop 2')
else n1==1 && n2==1;
c=2
d=n-1
disp('Loop 3')
else
disp('Something else!')
end
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