Length of runs of same number in an array

Hi,

I have a 10x1 vector, a = [-1 -1 0 0 0 -1 1 -1 1 1].

How can I find the number of times a number occurs continuously (i.e. if the number is -1, how many times does it occur in a row.). I want my result matrix to be [2 3 1 1 1 2]

Any help would be appreciated! Thanks,

DB

Answer 1

[Stephen23]

>> V = [-1,-1,0,0,0,-1,1,-1,1,1];
>> diff(find([1,diff(V),1]))
ans =
     2     3     1     1     1     2

[dan berkowitz]

Much appreciated!