Counting days by month

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dan berkowitz
dan berkowitz on 22 Oct 2017
Commented: Andrei Bobrov on 23 Oct 2017
hi,
i have a 100x11 char array with dates (e.g. '03-Jan-2006'). how can i create an array with the number of days in each unique month that appear in my date array. (e.g. if i have two days in january 2006, then i want it to return 2). any help would be appreciated. thx in advance.
DB

Accepted Answer

Andrei Bobrov
Andrei Bobrov on 22 Oct 2017
Edited: Andrei Bobrov on 22 Oct 2017
Here A - your array "100x11 char array with dates (e.g. '03-Jan-2006')"
z = datetime(A);
T = table(datetime(z,'F','MMM-uuuu'),eomday(year(z),month(z)),'v',{'date','days'});
  4 Comments
Andrei Bobrov
Andrei Bobrov on 23 Oct 2017
[y,m] = ymd(z);
or
[y,m] = datevec(z);

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More Answers (1)

KL
KL on 22 Oct 2017
Edited: KL on 22 Oct 2017
It's better to change your char array into datetime vector
dt_array = datetime(char_array,'InputFormat','dd-MMM-yyyy')
and then you can use
numOfDays = nnz(dt_array.Month==your_month)

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