Convert a vector into a structure array field
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x= [2; 8; 6; 3; 7; 8];
for i=1:numel(x)
s(i).x=x(i);
end
Do the same, but without cycle.
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Accepted Answer
Ray
on 20 Oct 2017
If struct s does not exist yet, you could use:
s = struct('x', num2cell(x));
3 Comments
Walter Roberson
on 20 Oct 2017
if x is the same length as the number of entries in the struct array s, then
temp = num2cell(x);
[s.x] = temp{:};
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