TABLE OF 2 ROWS AND 12 COLUMNS

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F.O
F.O on 10 Oct 2017
Commented: Walter Roberson on 11 Oct 2017
Hi,I want to make a TABLE OF 2 ROWS AND 12 COLUMNS WITH YEAR IN THE FIRST ROW AND NUMBER OF EARTHQUAKES IN THE SECOND ROW.
year=[2005 2006 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 ];
n_of_earthquakes=[1 2 4 0 1 1 1 2 2 1 1 0]

Accepted Answer

Image Analyst
Image Analyst on 11 Oct 2017
You can't have a table like that. You can however have them in columns:
year=[2005 2006 2007 2008 2009 2010 2011 2012 2013 2014 2015 2016 ];
n_of_earthquakes=[1 2 4 0 1 1 1 2 2 1 1 0]
t = table(year', n_of_earthquakes', 'VariableNames', {'year', 'n_of_earthquakes'})
If you want a matrix (a regular double numerical array) rather than a "table" variable, you can just use seimcolon:
m = [year; n_of_earthquakes]
  1 Comment
F.O
F.O on 11 Oct 2017
Thanks ,this looks good.

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More Answers (1)

Walter Roberson
Walter Roberson on 10 Oct 2017
year = 1973 : 1984;
earthquakes = randi(10000, 1, 12);
YourTable = array2table([year; earthquakes], 'RowNames', {'year', '# earthquakes'})
  6 Comments
Walter Roberson
Walter Roberson on 11 Oct 2017
That command take the vector year, and for each element of it, applies the function @(Y) sprintf('yr%d', Y) . That function converts the numeric element to a string and puts the characters 'yr' in front of that, giving a character vector as a result for each numeric element. The 'uniform', 0 option tells MATLAB to put the results into a cell array, so the end result stored in ylab is a cell array, each element of which is a character vector that starts with 'yr' and then followed by the year.
Starting in R2017a, the entire line can be replaced with
ylab = "yr" + year;

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