reshaping cell containing double arrays

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MiauMiau
MiauMiau on 10 Oct 2017
Edited: Guillaume on 10 Oct 2017
Hi,
I have (as an example) the following cell array:
test =
1×4 cell array
[40×1 double] [40×1 double] [40×1 double] [40×1 double]
I want test to be a 1 x 1 cell, containing the double arrays (from left to right) as one double array of dimension 160 x 1. reshape(test,[160,1]) does not work directly here. What can I do?

Answers (3)

KSSV
KSSV on 10 Oct 2017
Edited: KSSV on 10 Oct 2017
test = cell(1,4) ;
for i = 1:4
test{i} = rand(40,1) ;
end
iwant = cell2mat(test) ;
iwant = {iwant(:)} ;
  2 Comments
MiauMiau
MiauMiau on 10 Oct 2017
Is there no quicker way than looping?
Guillaume
Guillaume on 10 Oct 2017
The loop is only to build the demo data.

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Guillaume
Guillaume on 10 Oct 2017
That's because what you want is not reshaping but a concatenation. (The matrices may not be contiguous in memory):
test = [test{:}]
  2 Comments
MiauMiau
MiauMiau on 10 Oct 2017
That is giving me a 40x4 matrix...?!
Guillaume
Guillaume on 10 Oct 2017
Edited: Guillaume on 10 Oct 2017
Oh yes, your vectors are column vectors. Concatenate them vertically then:
test = vertcat(test{:})

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KL
KL on 10 Oct 2017
Edited: KL on 10 Oct 2017
test = cell2mat(test');
this?

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