Divide histogram in three parts

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Hi, I want to divide the histogram in three parts and define the ranges of three parts.
minRed = min(red(:));
maxRed = max(red(:));
AvgRed = (minRed+maxRed)/3;
AvgRed2 = AvgRed+AvgRed;
But sometimes the value of AvgRed becomes less than minRed and value of AvgRed2 exceeds the maxRed. What is the correct way to do this?

Accepted Answer

Walter Roberson
Walter Roberson on 28 Feb 2017
A + (B - A) /3
A + (B - A) /3 *2
  2 Comments
Walter Roberson
Walter Roberson on 28 Feb 2017
1-0.5459 is 0.4541. Divide by 3 gives 0.15136. Add 0.5459 gives 0.69726.

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