watching PID controller output value at perticular point

I am implementing PID controller on the system 1/s......

My question is when I write the command pidtool and get the new window in that there are list of paramenters..... I want to see the output of controller at perticular point i.e. Pout=Kp*e(t)+P0....

other thing is if my system is 1/s then as in step response it becomes 1/s^2 and then Laplace inverse will give output equation.... in case of only P it would be Kp*e(t)*L^-1(1/s).... is it??

Answer 1

[Sam Chak]

@rathod ujjval rameshbhai, Since no performance requirements are specified, the pidtune() command can be used to automatically search for the control gains that stabilize the unstable open-loop system.

% Plant (unstable open loop system)
Gp  = tf(1, [1 0])

Gp =
 
  1
  -
  s
 
Continuous-time transfer function.

% Compensator
% wc  = 1;
% [Gc, info]  = pidtune(Gp, 'pid', wc)
[Gc, info]  = pidtune(Gp, 'pid')

Gc =
 
             1 
  Kp + Ki * ---
             s 

  with Kp = 0.981, Ki = 0.193
 
Continuous-time PI controller in parallel form.

info = struct with fields:
                Stable: 1
    CrossoverFrequency: 1
           PhaseMargin: 78.8791

% Closed-loop feedback system
Gcl = feedback(series(Gc, Gp), 1)

Gcl =
 
     0.9812 s + 0.1929
  -----------------------
  s^2 + 0.9812 s + 0.1929
 
Continuous-time transfer function.

% step response
step(Gcl), grid on