xlsread not able to reference my sheet names.

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Good afternoon,
I've never had this problem before, I'm certain it must be a pretty easy fix.
I'm trying to open an excel file, using xlsread. I have my program on a loop though specifying that each pass it should use a sheet of a different name. It keeps telling me though that the sheet name does not exist, but when I use xlsinfo it tells me that the sheet name is there.
DATA = xlsread('DATA1', 12)
I'm just a bit stumped as to how to get around this.
Any advice would be very much appreciated!
Thanks
  2 Comments
Stephen23
Stephen23 on 6 Jan 2016
Edited: Stephen23 on 6 Jan 2016
@Chameleon17: for this forum please don't put leading space characters in front of each line of your text, because this will be formatted as monospaced text (i.e. code). I just removed your leading space characters, and you can see now how the text of your question is normal text.
Renato Agurto
Renato Agurto on 6 Jan 2016
I that the actual command you are using? where are you writing the filename? You also have to write the sheet name OR the number, not both

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Answers (2)

Image Analyst
Image Analyst on 6 Jan 2016
Are you sure you have 12 worksheets in the workbook? Have you tried using the name of the sheet instead of it's number? Can you attach the data.xlsx workbook file to your posting with the paperclip icon?
  4 Comments
Image Analyst
Image Analyst on 6 Jan 2016
I saw you just posted that this did not work. However, I'm not seeing your workbook attached anywhere so that anyone can try it. Are you able to do that? You can take out any proprietary numbers and strings if you want first.
Image Analyst
Image Analyst on 7 Jan 2016
Are you sure it's twelve and not (capital i)2?

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Renato Agurto
Renato Agurto on 6 Jan 2016
Edited: Renato Agurto on 6 Jan 2016
The name of the sheet should be a string. You should use then:
DATA = xlsread('DATA1.xlsx', '12')
If you use a number it will select the sheet number 12 (if you have 12 sheets or more of course)
  3 Comments
Renato Agurto
Renato Agurto on 6 Jan 2016
can you post the results of:
[status, sheets] = xlsfinfo('DATA1.xlsx')
and the error message of:
DATA = xlsread('DATA1.xlsx', '12')
Walter Roberson
Walter Roberson on 6 Jan 2016
After you run the above, please also post
sheets{1}, (sheets{1}+0)
so we can check for unexpected characters in the name.

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