Find size of array

For A_Set1{2}

ans =

    {1x3 cell}    {1x3 cell}
    {1x3 cell}    {1x3 cell}
    {1x3 cell}    {1x3 cell}
    {1x4 cell}    {1x3 cell}
    {1x4 cell}    {1x3 cell}
    {1x4 cell}    {1x3 cell}

When I tried to find the size, I get the error function:

>> size(A_Set1{2})

>> Function 'subsindex' is not defined for values of class 'cell'

Yet when the length is used,

>> length(A_Set1{2}) = 6

How do you find the size of the array then i.e. [6 2]?

EDIT: should have written "size" instead of "Size"

Answer 1

[the cyclist]

Not sure, but I have a couple guesses. You are showing that you used Size rather than size. MATLAB is case-sensitive.

You may have accidentally defined size to be some other command or function. What do you get if you type

which size

You would get something like

built-in (/Applications/MATLAB_R2015b.app/toolbox/matlab/elmat/size)

Answer 2

[Image Analyst]

length() gives the longest dimension (regardless of which direction it's going in), whereas size() gives all the dimensions - that's why length() gives 6. A_Set1 is a cell array with at least 2 cells. The second cell of A_Set1 contains another cell array, and that cell array is 6 rows by 2 columns. I would think it should work so all I can suggest is that you try what cyclist suggested, and attach a .mat file with your variable if that still does not work. Also, what does this produce:

>> cell2 = A_Set1{2}
>> numel(cell2)
>> whos cell2