Calculating values from an iterative map

3 views (last 30 days)
Ollie
Ollie on 13 Aug 2015
Edited: Ollie on 13 Aug 2015
I need to write a Matlab code that will calculate the x10 value for the following iterative map that doesn't use fsolve,\ or inv commands, given x0= -3.
I also need a code that will calculate:
for the same iterative map.
Any help would be very appreciated :)
  1 Comment
Ollie
Ollie on 13 Aug 2015
Thanks, I think I understand how to do the first part now although I am still struggling with the second part. Is there anyone who could give me the specific code to program it?

Sign in to comment.

Answers (2)

Walter Roberson
Walter Roberson on 13 Aug 2015
Use a "for" loop. Inside the "for" use "if" and "elseif".
  2 Comments
Walter Roberson
Walter Roberson on 13 Aug 2015
x(1) = 0;
for n = 1 : 10
xn = x(n);
first_expression = some calculation with xn
second_expression = some other calculation with xn
if first_expression < second_expression
xn1 = some result calculated with xn
else
....
if third_expression < fourth_expression
...
xn1 = ...
else
...
xn1 = ....
end
end
x(n+1) = xn1
end
Ollie
Ollie on 13 Aug 2015
Edited: Ollie on 13 Aug 2015
Thanks for the reply. This is the code I have attempted:
x(1)=-3;
for n = 1:10
xn = x(n);
expression1 = xn^4 + 8;
expression2 = 1/(xn*sqrt(abs(xn)));
expression3 = 3 - xn^2;
if expression1 <= expression2
xn1 = sqrt(abs(xn)) - 3*xn
else
if expression3 <= expression2
xn1 = -1/xn*tan(xn)
else
xn1 = -3/xn
end
end
x(n+1)=xn1
end
The code is not returning the correct result. Can you tell me how to fix it?

Sign in to comment.


Purushottama Rao
Purushottama Rao on 13 Aug 2015
for the second part,
s=0;
for n=4:8
k=(x(n-1)-2)+(x(n-1)+1);
s=s+k;
end
disp(s)

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!