Huffman coding and decoding for image(JPEG, BMP)
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I have to implement huffman encoding and decoding for a '.bmp' image without using the inbuilt matlab function like huffmandict, huffmanenco and huffmandeco.
Can anybody help me by sending me the source code?
Moreover, I have done the encoding part but I am not able to do the decoding. I have no idea as how to reconstruct the image through decoding.
4 Comments
Dimple Anandpara
on 23 Jun 2015
i implement given code of huffman encoding for a .bmp file but the encode string size more then actual size of file can u explain why?
Walter Roberson
on 23 Jun 2015
That is possible. You need to store the code dictionary as well as the encoding. With 256 different symbols possible, unless at least half of them are never used, you can be sure that some of the encodings will be at least 8 bits, the original length. When the probabilities are about equally distributed each of the symbols would come out as 8 bits, so saving nothing for the encoded part. But you need to save the dictionary as well and that takes room.
Huffman encoding is a lossless encoding, so you need to have as much "information" stored in the encoded version as in the unencoded version. It doesn't begin to save space on the encoding until some of the symbols are at least twice as probable as some of the others or at least half the potential symbols are never unused, which are situations that would allow it to save 1 bit per occurrence. Those bits saved have to add up to the size of the saved dictionary before you get any net savings on the storage.
Efficient storage of the dictionary takes some thought since each of the entries is a variable number of bits -- the bit pattern and the symbol it decodes to. And remember to account for the end-of-stream marker or some other method of indicating where the end of the stream of bits is, since it will not generally be at a byte boundary so you can't tell by end-of-file.
Jasmina Vanasiwala
on 12 Dec 2016
I have to implement huffman encoding and decoding for a 'jpeg' image using C or C++. Please anyone help me by sending the source code?
Walter Roberson
on 12 Dec 2016
- this is a resource for MATLAB questions not C or C++
- there are already a lot of public sources for that task including libjpeg
- if we send you source then you would not have implemented it. Would we get the academic credit or would you?
Accepted Answer
More Answers (2)
Falak
on 4 May 2012
Try this one... just change to your required image
%Author Name:Falak Shah
%Target: To huffman encode and decode user entered string
%--------------------------------------------------------------------------
string=input('enter the string in inverted commas'); %input string
symbol=[]; %initialise variables
count=[];
j=1;
%------------------------------------------loop to separate symbols and how many times they occur
for i=1:length(string)
flag=0;
flag=ismember(symbol,string(i)); %symbols
if sum(flag)==0
symbol(j) = string(i);
k=ismember(string,string(i));
c=sum(k); %no of times it occurs
count(j) = c;
j=j+1;
end
end
ent=0;
total=sum(count); %total no of symbols
prob=[];
%-----------------------------------------for loop to find probability and
%entropy
for i=1:1:size((count)');
prob(i)=count(i)/total;
ent=ent-prob(i)*log2(prob(i));
end
var=0;
%-----------------------------------------function to create dictionary
[dict avglen]=huffmandict(symbol,prob);
% print the dictionary.
temp = dict;
for i = 1:length(temp)
temp{i,2} = num2str(temp{i,2});
var=var+(length(dict{i,2})-avglen)^2; %variance calculation
end
temp
%-----------------------------------------encoder and decoder functions
sig_encoded=huffmanenco(string,dict)
deco=huffmandeco(sig_encoded,dict);
equal = isequal(string,deco)
%-----------------------------------------decoded string and output
%variables
str ='';
for i=1:length(deco)
str= strcat(str,deco(i));
end
str
ent
avglen
var
8 Comments
sailaja
on 31 Jan 2014
its not working for an image
sailaja
on 31 Jan 2014
how to use this code for an image
Walter Roberson
on 31 Jan 2014
Change the input() call to,
filename = input('enter the image file name', 's');
string = imread(filename);
string = string(:);
projecte
on 26 Apr 2014
hi how can i decode a image from a secret image in the same format
juveria fatima
on 17 Feb 2018
filename = input('enter the image file name', 's');
what is 's' here
satyendra kumar
on 23 Mar 2019
they not work properly.....how can solve it?
%Target: To huffman encode and decode user entered string
%--------------------------------------------------------------------------
filename = input('enter the image file name', 's');
string = imread('cameraman.tif');
string = string(:);
symbol=[]; %initialise variables
count=[];
j=1;
%------------------------------------------loop to separate symbols and how many times they occur
for i=1:length(string)
flag=0;
flag=ismember(symbol,string(i)); %symbols
if sum(flag)==0
symbol(j) = string(i);
k=ismember(string,string(i));
c=sum(k); %no of times it occurs
count(j) = c;
j=j+1;
end
end
ent=0;
total=sum(count); %total no of symbols
prob=[];
%-----------------------------------------for loop to find probability and
%entropy
for i=1:1:size((count)');
prob(i)=count(i)/total;
ent=ent-prob(i)*log2(prob(i));
end
var=0;
%-----------------------------------------function to create dictionary
[dict avglen]=huffmandict(symbol,prob);
% print the dictionary.
temp = dict;
for i = 1:length(temp)
temp{i,2} = num2str(temp{i,2});
var=var+(length(dict{i,2})-avglen)^2; %variance calculation
end
temp
%-----------------------------------------encoder and decoder functions
sig_encoded=huffmanenco(string,dict)
deco=huffmandeco(sig_encoded,dict);
equal = isequal(string,deco)
%-----------------------------------------decoded string and output
%variables
str ='';
for i=1:length(deco)
str= strcat(str,deco(i));
end
str
ent
avglen
var
Walter Roberson
on 23 Mar 2019
What leads you to say that it does not work?
Harshil Patel
on 28 Apr 2020
I ran the code in matlab 2020a, and it generated some otput with some values for str, ent, avglen and var for an image input. So, how do I know if it's correct?
slama najla
on 19 May 2012
0 votes
Hello please is that you can help me? is that you can send me your registration code files before you get the picture compressed as I encounter the same problem as let go of compressed image is a very superior picture framer and my original remark that the fault is in the recording files. thank you in advance
9 Comments
Walter Roberson
on 19 May 2012
The dictionary is dependent on the image being encoded. Having the dictionary for a different image would not help you.
SS
on 15 Oct 2019
Can we use huffman coding for both lossy and lossless image compression??
Walter Roberson
on 15 Oct 2019
Yes. After you derive your symbols and remove the ones with sufficiently low probability or merge them with the nearest higher probability symbol, you can do Huffman encoding on what is left.
SS
on 15 Oct 2019
Thank you
SS
on 23 Nov 2019
how to create huffman tree diagram for lossless image compression?
Walter Roberson
on 23 Nov 2019
huffmandict()
SS
on 27 Nov 2019
rng('default') % For reproducibility
X = rand(10,3);
In this code, what will be the value of X for my image..???
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