how can I create a matrix from calculated answers
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I have this answers and I want to put them in a diagonal matrix.Pls help me!
y =
0.0025 + 0.0155i
y =
0.0030 + 0.0171i
y =
0.0038 + 0.0191i
y =
0.0049 + 0.0216i
y =
0.0066 + 0.0248i
y =
0.0092 + 0.0289i
y =
0.0137 + 0.0344i
y =
0.0220 + 0.0414i
y =
0.0388 + 0.0487i
y =
0.0717 + 0.0450i
y =
1000000
y =
0.0717 - 0.0450i
y =
0.0388 - 0.0487i
y =
0.0220 - 0.0414i
y =
0.0137 - 0.0344i
y =
0.0092 - 0.0289i
y =
0.0066 - 0.0248i
y =
0.0049 - 0.0216i
y =
0.0038 - 0.0191i
y =
0.0030 - 0.0171i
y =
0.0025 - 0.0155i
2 Comments
James Tursa
on 26 Feb 2011
Can you show the code that generates these numbers? You can pre-allocate a result and then assign them to the appropriate spots in the result, or maybe there is a better vectorized solution, but we can't tell without seeing your code.
Accepted Answer
Matt Fig
on 26 Feb 2011
Don't you think it would help if you showed us how that "this answers" was generated? It really would.
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EDIT
O.k., here is one way, with your FOR loop:
clear all
f=1E3;
L1=1E-3;
L2=100;
Rs=1E-6;
R1=10;
w=2*pi*f;
k=10;
z1=eye(21); % I assume you want this to be the matrix.
cnt = 1;
for a = -11:k-1
omega = w*(a+1);
z1(cnt,cnt)=1/(Rs+(j*omega*L2*((R1+j*omega*L1)))/(R1+j*omega*(L1+L2)));
cnt = cnt + 1;
end
Or, simpler:
f=1E3;
L1=1E-3;
L2=100;
Rs=1E-6;
R1=10;
w=2*pi*f;
k=10;
omega = w*((-11:k-1)+1);
z1_2 = diag(1./(Rs+(j*omega*L2.*((R1+j*omega*L1)))./(R1+j*omega*(L1+L2))));
Now if you compare z1 and z1_2, you will see that they are equal.
2 Comments
More Answers (2)
Matt Tearle
on 26 Feb 2011
M = zeros(n);
for k = 1:n
% calculate y
M(k,k) = y;
end
Or, preferably, if you can calculate all the y values in a vector, as explained here you can then do
M(1:n+1:end) = y;
Edit: fixed typo ( n+1 instead of n )
4 Comments
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