??? Error using ==> eq Matrix dimensions must agree.

orders are min_cost = min(x(:));

 [pnode, node] = find(x == min_cost);
 [row, column]=find(My_matrix == pnode);
 [rows, columns]=find(My_matrix==node);
and i get this error
Error in ==> lisi_dokimes4 at 635
           [row, column]=find(My_matrix
           == pnode);

and the min_cost instead of taking one value it takes an array,x is a matrix 101X101 My_matrix has dimensions 10X14

[Adam]

diadromes_final doesn't appear anywhere in that code snippet.

And why start another thread with what is essentially the same question you just asked a few minutes ago?

[Giannakis Stoukas]

I changed it here and i wrote it My_matrix instead of diadromes_final to understand what "diadromes_final" is.Diadromes_final is the matrix My_matrix.Where i have write My_matrix it is diadromes_final,but i forgot to change it in the error,so the error is

Error in ==> lisi_dokimes4 at 635 [row, column]=find(My_matrix == pnode);

[Adam]

You need to give clear full details of the sizes of every variable in the code snippet if you want help to solve this, otherwise we are just guessing at what might be the problem.

Given the line of the error, the following variables are all relevant:

x
min_cost
pnode
My_matrix

depending if the following line also has problems node may also be relevant.

Answer 1

[Jan]

diadromes_final and pnode have different sizes. As long as you do not post the code, which creates these two variables, we do not have the chance to guess the reason for this. So I suggest to use the debugger and step through the code line by line to find out, where the different sizes are comming from.

[EDITED] So let me clarify your question:

min_cost = min(x(:))
[pnode, node] = find(x == min_cost);
[row, column] = find(My_matrix == pnode);

Now it is not clear, how x and my_matrix are connected. But the error message means, that pnode and My_matrix have different sizes. Why do you assume that both have the same size? Perhaps you want ismember instead of the == comparison?

[Giannakis Stoukas]

I changed it here and i wrote it My_matrix instead of diadromes_final to understand what "diadromes_final" is.Diadromes_final is the matrix My_matrix.Where i have write My_matrix it is diadromes_final,but i forgot to change it in the error,so the error is

Error in ==> lisi_dokimes4 at 635 [row, column]=find(My_matrix == pnode);

[Jan]

Then please edit the question and do not post important details in comments, where they are found too late only.

See [EDITED]

[Giannakis Stoukas]

Maybe the "==" isn't right and i have to use something else.In the problem i have a matrix x and a variable min_cost and i want to find in which row is the value (pnode) and in which column (pnode).After this,i have another matrix,My_matrix,and i want to find in which rows and columns are the pnode and node in the matrix My_matrix.

[Jan]

And what should happen, if the minimal value appears multiple times in the matrix?

Please provide a relevant small example of the inputs and the wanted outputs. The description as text does nopt allow to create a useful answer.