fprintf automatic spacing for strings of different lenghts

48 views (last 30 days)
Hi,
how do i evenly space if I print this text using fprintf, in the example 1 below is what I get but I would like to output in the format of example 2, is there a way to automate the spacing if we the consecutive places and I have a string(name of place n) of different lenghts?
where cities is an array of strings show in the examples below and paths is a vector
for i = 1:(length(path)-1)
fprintf('%s --> %s (Distance = %s km)\n', cities(path(i)), cities(path(i+1)), num2str(matDist(min(... [path(i) path(i+1)]), max([path(i) path(i+1)]))));
end
fprintf('%s --> %s (Distance = %s km)\n', cities(path(end)), cities(path(1)), num2str(matDist(min(... [path(1) path(end)]), max([path(1) path(end)]))));
Example 1
Path and distance
----------------------------------------
Case fileName | Origin = Vila Ló(city 1)
----------------------------------------
Total Distance = 414 km
Vila Ló --> Pião (Distance = 46 km)
Pião --> Chão de Frades (Distance = 73 km)
Chão de Frades --> Salmorrete (Distance = 205 km)
Salmorrete --> Tortolindo (Distance = 33 km)
Tortolindo--> Vila Ló (Distance = 57 km)
Example 2
Path and distance
----------------------------------------
Case fileName | Origin = Vila Ló(place 1)
----------------------------------------
Total Distance = 414 km
Vila Ló --> Pião (Distance = 46 km)
Pião --> Chão de Frades (Distance = 73 km)
Chão de Frades --> Salmorrete (Distance = 205 km)
Salmorrete --> Tortolindo (Distance = 33 km)
Tortolindo --> Vila Ló (Distance = 57 km)
  2 Comments
Dyuman Joshi
Dyuman Joshi on 16 Oct 2023
Moved: Dyuman Joshi on 16 Oct 2023
Vectorized version -
%Sample data
cities1 = ["Vila Ló", "Pião", "Chão de Frades", "Salmorrete", "Tortolindo"];
cities2 = cities1([2 3 4 5 1]);
distance = [46 73 205 33 57];
%Convert the distance to strings with the desired precision
distance = compose("%d", distance);
n = repelem(max(strlength(cities1)),1,numel(cities1));
%If you need to add more spaces in between, modify n accordingly
%For e.g
%n = n+5;
fprintf('%-*s --> %-*s (Distance = %s km)\n', [n;cities1;n;cities2;distance])
Vila Ló --> Pião (Distance = 46 km) Pião --> Chão de Frades (Distance = 73 km) Chão de Frades --> Salmorrete (Distance = 205 km) Salmorrete --> Tortolindo (Distance = 33 km) Tortolindo --> Vila Ló (Distance = 57 km)

Sign in to comment.

Accepted Answer

Voss
Voss on 16 Oct 2023
cities = ["Pasadena","Urbana-Champaign","Cambridge"];
path = 1:numel(cities);
d = [3200 1600 4800]; % using a vector of distances since I don't have your function matDist()
n = max(strlength(cities));
for i = 1:(length(path)-1)
fprintf('%-*s --> %-*s (Distance = %.f km)\n', n, cities(path(i)), n, cities(path(i+1)), d(i));
end
Pasadena --> Urbana-Champaign (Distance = 3200 km) Urbana-Champaign --> Cambridge (Distance = 1600 km)
fprintf('%-*s --> %-*s (Distance = %.f km)\n', n, cities(path(end)), n, cities(path(1)), d(end));
Cambridge --> Pasadena (Distance = 4800 km)

More Answers (1)

Florian Bidaud
Florian Bidaud on 16 Oct 2023
Edited: Florian Bidaud on 16 Oct 2023
Something like this should do
cities = ["Vila Lo" "Piao" "Chao de Frades" "Salmorrete" "Tortolindo"];
path = [1 2 3 4 5];
distance = [46 73 205 3357]; % Should be replaced by your function matDist
max_city_len = max(strlength(cities));
for i = 1:(length(path)-1)
fprintf('%s %s --> %s %s (Distance = %s km)\n', cities(path(i)),repmat(' ',1,max_city_len-strlength(cities(path(i)))+1), repmat(' ',1,max_city_len-strlength(cities(path(i+1)))+1), cities(path(i+1)), num2str(distance(i)));
end
Vila Lo --> Piao (Distance = 46 km) Piao --> Chao de Frades (Distance = 73 km) Chao de Frades --> Salmorrete (Distance = 205 km) Salmorrete --> Tortolindo (Distance = 3357 km)
fprintf('%s %s --> %s %s (Distance = %s km)\n', cities(path(end)), repmat(' ',1,max_city_len-strlength(cities(path(end)))+1), repmat(' ',1,max_city_len-strlength(cities(path(1)))+1), cities(path(1)), num2str(distance(end)));
Tortolindo --> Vila Lo (Distance = 3357 km)

Categories

Find more on Environment and Settings in Help Center and File Exchange

Products

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!