Please Help with Number Arrangement

Good Day!

I am having a problem regarding arrangement of numbers.

I have a matrix of

[1 2;
 2 3;
 3 4;
 3 5;
 4 6;
 6 7];

First, I want to find the end node. In this example, 5. Then 5 is connected to 3 and a process will be performed. After that, the program must go to 7 which is connected to 6 and 4. when the program detects that the number is 4 it will stop and another operation will be performed.

Please help me. Any tips will do.

Thanks

Regards Dhon Xean

[John D'Errico]

Totally confusing. You tell us that 5 is connected to 3. Then it goes to 7. How does that happen? How can we know what you are doing if you do not explain it?

I am tempted to look at the matrix as a set of undirected edges in a graph. But if we start at node 5, then go to 3, why is not the NEXT step to node 4 or to node 2, as both of those nodes seem to be connected to node 3.

You need to explain your problem clearly, else it becomes impossible to answer.

[DhonXean Bobis]

Sorry for the vague question

Currently, I am working on a forward/backward sweep method for power systems.

The method specified was that you need to start from the end node. The example data i gave was for the sending node and receiving node, column respectively.

Node 7 was an end node connected to 6, which was a junction node. After evaluating processes, 6 and 7 are connected, then another function going to node 4, I need to evaluate other end nodes, for example, node 5 and if it detects that it is on a junction node, here node 3, another process will be performed.

Thanks and sorry for the vague question.

Regards Dhon Xean

Answer 1

[Joep]

Do you mean something like this?

prompt = 'What is your test value? \n';
TestNo=input(prompt); %Test No.

a=[1 2;
 2 3;
 3 4;
 3 5;
 4 6;
 6 7];

b= a(:,2)==TestNo; %Location

c=a(b,1);

d= a(:,2)==c;

if d == zeros(size(d))
    if c == 4;
        msgbox('another program will start');  
    end
else
    e= a(d,1);
    if e == 4;
        msgbox('another program will start');
    end
end

[DhonXean Bobis]

After evaluating this code. I think it will be a big help.

Thank you very much.

And sorry for the vague question.