# help required for fixed point conversion

30 views (last 30 days)

Show older comments

##### 0 Comments

### Accepted Answer

Andy Bartlett
on 4 Apr 2023

Edited: Andy Bartlett
on 4 Apr 2023

Mapping an A2D to a fixed-point data type

One way to map an A2D converter to a fixed-point data type is to use two real-world-value and stored-integer pairs.

You then solve a pair of affine equations

realWorldValue1 = Slope * storedIntegerValue1 + Bias

realWorldValue2 = Slope * storedIntegerValue2 + Bias

and enter those in the data type

fixdt( isSigned, WordLength, Slope, Bias)

realWorldValue1 = 10; % Volts

storedIntegerValue1 = 32767;

realWorldValue2 = -10; % Volts

storedIntegerValue2 = -32767; % Is this the correct value?

% Solve for data types Slope and Bias

% V = Slope * Q + Bias

%

% form as a Matrix Equation

% Vvec = [ Qvec ones ] * [Slope; Bias]

% Vvec = QOMat * slopeBiasVector

% then use backslash

% slopeBiasVector = QOMat \ Vvec

Vvec = [realWorldValue1; realWorldValue2];

SIvec = [storedIntegerValue1; storedIntegerValue2]

QOMat = [SIvec ones(numel(SIvec),1)];

slopeBiasVector = QOMat \ Vvec;

Slope = slopeBiasVector(1)

Bias = slopeBiasVector(2)

isSigned = any( SIvec < 0 )

wordLength = max( ceil( log2( abs( double(SIvec) ) ) ) )

a2dNumericType = numerictype( isSigned, wordLength,Slope,Bias)

% Sanity check

checkRealWorldValue1 = Slope * storedIntegerValue1 + Bias

checkRealWorldValue2 = Slope * storedIntegerValue2 + Bias

err1 = checkRealWorldValue1 - realWorldValue1

err2 = checkRealWorldValue2 - realWorldValue2

##### 0 Comments

### More Answers (2)

Andy Bartlett
on 29 Mar 2023

Hi Gary,

That portion of your model will involve 4 data types.

- Digital measurement of output signal from analog plant
- Set point signal
- Accumulator type used to do the math inside the Subtraction block
- Output of that subtraction block feed to your controller logic

Normally, the fixed-point tool should be able to pick separate data types and scaling for each of those signals.

For the range values and data type for the subtractor output, everything looks pretty good.

errorSignalExample = fi([-0.00021679, 0.01076],1,32,37)

rangeErrorSignalDataType = range(errorSignalExample)

The issues are likely coming from else where in the model.

Try setting the model's diagnostics for Signals with Saturating and Wrapping overflows to Warning, then rerun the simulation. This should help isolate sources of overflow.

If overflows are occurring, then try rerunning the Fixed-Point Tool workflow but give a bigger Safety Margin before proposing data types. If there are fixed-point types in the model at the start of the workflow, then turn on Data Type Override double when Collecting Ranges.

If overflows are not the issue, turn on signal logging for several key signals in the model. Repeat the fixed-point tool workflow with Data Type Override double on during collect ranges. Then at the end of the workflow click Compare Signals and use Simulation Data Inspector to isolate where the doubles signal traces first start to diverge from the fixed-point traces. This will point you to a place in the model to look more carefully at the math and the data types.

##### 3 Comments

Andy Bartlett
on 30 Mar 2023

Change the data type of the accumulator to move one bit from the precision end to the range end, thus doubling the range. This will allow +1 to be represented without overflow.

dt = fixdt(1,32,30)

representableRange = range( numerictype(dt) )

Andy Bartlett
on 30 Mar 2023

The number 395 is how many times that block in the model overflowed during the previous simulation. Suppose the element was a data type conversion block with input int16 and the output uint8. Suppose the input at one time step in the simulation was 260. Since 260 exceeds the maximum representable value, 255, of the output data type, an overflow will occur. The block could be configured to handle overflows with saturation in which case the output would be 255, and that would increase the count of "overflow saturations" for the block by 1. Alternately, the block could be configured to handle overflows with Modulo 2^Nbits wrapping in which case the output would be mod(260,2^8) = 4, and that would increase the count of "overflow wraps" for the block by 1.

So 395 overflow wraps means that during the previous instrumented simulation that block had 395 overflow events handled by Modulo 2^Nbits wrapping.

The count of overflows does NOT indicate what new data type is required to avoid overflows. Overflows due to values slightly too big for the output data type count as one overflow event, and overflows due to values 1000X to big for the output data type also count as just one overflow event.

Collecting the simulation minimum and maximum values is what helps pick a type that will avoid overflows. Calling fi with the simulation min and max will show the type thats big enough.

format long g

simulationMinMax = [-13.333333333333334, 12.666666666666666]; % Collected by Fixed-Point Tool or some other way

safetyMarginPercent = 25;

%

% Expanded range to cover

%

expandedMinMax = (1 + safetyMarginPercent/100) .* simulationMinMax

%

% Data type container attributes

% Signedness

% WordLength

%

isSigned = 1; % manually set

%isSigned = any( expandedMinMax < 0 ) % use range to see of negatives needed

wordLength = 8; % manually set

%

% Automatically determine scaling

% using fi's best precision mode (just don't specify scaling)

%

quantizedExpandedMinMax = fi( expandedMinMax, isSigned, wordLength)

bestPrecisionNumericType = numerictype(quantizedExpandedMinMax)

representableRangeOfBestPrecisionDataType = range(bestPrecisionNumericType)

##### 5 Comments

Andy Bartlett
on 7 Apr 2023

>> How do I convert fixdt(1,32,30) to fixdt(1,16,14) without loss of precision?

You can't avoid precision loss. You are dropping 16 bits from the precision end of the variable.

If you use the fastest, leanest conversion, Round to Floor, that you will introduce quantization error of 0 to just under 1 bit. In real world value terms, the absolutie quantization error is in the range 0 to Slope, where Slope = 2^-14;

You can cut the quantization error in half and balance around zero if you use Nearest rounding. With Nearest, the absolute quantization error will be 0 to 1/2 bits or in real world values 0 to 0.5*Slope = 2^-15. But keep in mind that round to nearest can overflow for values close to +1. If you turn on Saturation in the cast, quantization error will still be always be less or equal to half a bit. But if you allow the overflow cases to wrap modulo 2^N, then the quantization error will be huge for the overflowing cases.

### See Also

### Categories

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!