i want to restore the original binary image S by xor the two shares R1,R2

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S = imread('binary.png');
C = imread('text input.png');
[m, n] = size(S);
no = 2;
beta = 1;
R1 = zeros(m, n);
R2 = zeros(m, n);
for i = 1:m
for j = 1:n
d = rand;
if d < beta
"function T = algo2(S(i, j), no)";
R1(i, j) = T(1);
R2(i, j) = T(2);
else
if mod(n*C(i, j), no) == 0
R1(i, j) = C(i, j);
R2(i, j) = C(i, j);
else
f = randi([1 no]);
for k = 1:n
if k == f
R1(i, j) = 1 - C(i, j);
R2(i, j) = 1 - C(i, j);
elseif k < f
R1(i, j) = C(i, j);
R2(i, j) = C(i, j);
else
R1(i, j) = C(i, j);
R2(i, j) = C(i, j);
end
end
end
end
end
end
S_restored = bitxor(R1, R2);
imshow(S_restored);
this is the code for restore the original bianry image,in this the the line "function T = algo2(S(i, j), no)"; calls the another code algo2 for the 2 pixel shares...but the resulting image is full of black.i tried so many times to rectify it.help to get rid of the issue
code for algo2:
function T = algo2(S, n)
S=imread('text input.png');
meven=[0 0 0;
0 1 1;
1 0 1;
1 1 0];
modd=[0 0 1;
0 1 0;
1 0 0;
1 1 1];
no=1;
y =zeros(size(S));
R=zeros(size(S));
l=zeros(size(S));
for i = 1:size(S,1)
for j = 1:size(S,2)
if (S(i, j) == 0)
r=rand([no,2^no-1]);
disp(r)
ro=round(r*(size(meven,1)-1))+1;
disp(ro)
R(i,j)=meven(ro,1);
l(i,j)=meven(ro,2);
else
r=rand([no,2^no-1]);
disp(r)
ro = round(r*(size(modd,1)-1))+1;
disp(ro)
R(i,j)=modd(ro,1);
l(i,j)=modd(ro,2);
end
end
end
y(i,j)=S(i,j);
  2 Comments
Image Analyst
Image Analyst on 28 Mar 2023
No idea, because you forgot to attach your two input images. You didn't even attach screenshots, so I gave up at that point.
If you have any more questions, then attach your data and code to read it in with the paperclip icon after you read this:
Walter Roberson
Walter Roberson on 28 Mar 2023
"function T = algo2(S(i, j), no)";
That line just constructs a 1 x 1 string array in which the first element contains ['f' 'u' 'n' 'c' 't' 'i' 'o' 'n' ' ' 'T' ] and so on.

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