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为什么能正常运行的parfor代码封装成函数后无法运行?
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以下包含 parfor 的代码可以正常运行:
c = cell(1, 10);
parfor ii = 1:10
c{ii} = 1;
end
同样的代码包装成函数(仅仅添加一行function tempFcn()),即显示语法错误:输出变量 c 不能再 PARFOR 循环后使用:
function tempFcn()
c = cell(1, 10);
parfor ii = 1:10
c{ii} = 1;
end
请问这是什么原因?
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