- There is no break out of the forever while loop, so the code will never terminate on its own
- previouspower is never used
- pickangle11 is never used
- The distance calculation doesn't depend on anything in the loop
- pt is not defined anywhere
- x1, x2, y1, y2 are not defined anywhere
- Etc.

# How can I find the max value from many max values inside the " WHILE LOOP " ?

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if we run the code below we will get the maxpower in each round of "for loop" means the for loop starts from -28.64 up to +28.64 which means

20 steps. Now, the maxpower is obtained from each round (20 steps of the for loop). My question is how can I find the maximum value from many maxpower values inside while loop ?

Thanks in advance

Angleoption11 = [-28.6479 -27.5 -18.33 -13.75 -11 -9.16 -7.85 -6.87 -6.11 -5.5 5.5 6.11 6.87 7.85 9.16 11 13.75 18.33 27.5 28.6479];

while true

previouspower = currentpower;

for current_index1 = 1:numel(Angleoption11)

pickangle11 = Angleoption11(current_index1);

distance = sqrt((x1-x2.').^2 + (y1-y2.').^2)

currentpower=pt*distance

end

[maxpower, index]=max(currentpower);

end

##### 4 Comments

dpb
on 26 Jul 2022

Save the max you find each iteration in another array -- when the outer iteration is complete, then use max on that array.

Or, you can compare the new maximum to the previous each time and save the greater on each pass -- to do this you also must have a GlobalMax value that starts of first iteration holding the maximum; for subsequent does the comparison first.

### Accepted Answer

David Hill
on 26 Jul 2022

GlobalMax=-9999;

while true

for

%calculations

end

if maxpower>GlobalMax

GlobalMax=maxpower;

end

end

##### 3 Comments

David Hill
on 26 Jul 2022

while true

for

%calculations

end

if maxpower>GlobalMax

GlobalMax=maxpower;

else

break;%break when the maxpower stops increasing?

end

end

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