how to take an alternating range of elements from a vector to make two new vectors

Hello everyone,

I will try to explain the title with an example.

So let's say i have a vector (a 1x100)

a = [ 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0]

i want to extract only the 1s and the 0s in new vectors. so we will have two 1x50 vectors

a_1=[ 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1 1]

a_0=[ 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0]

is there a way to do that in matlab?

regards

Ali

Answer 1

[Voss]

a = [ 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0];

a_1 = a(a == 1); % elements of a where a equals 1
a_0 = a(a == 0); % elements of a where a equals 0

disp(a_1);

  Columns 1 through 37

     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1     1

  Columns 38 through 50

     1     1     1     1     1     1     1     1     1     1     1     1     1

disp(a_0);

  Columns 1 through 37

     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0     0

  Columns 38 through 50

     0     0     0     0     0     0     0     0     0     0     0     0     0

[Ali Albaidhani]

Thank you for your answer. I wrote a very simple example to explain the problem. I have different values in my measurement.

I want to take every 10 elements and skipping the next 10 till the end of the vector.

[Voss]

I see. Here's a way you can do that:

% a = [ 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0];
a = 1:100; % a different a to illustrate

a_temp = reshape(a,10,[]);
a_1 = reshape(a_temp(:,1:2:end),1,[]);
a_0 = reshape(a_temp(:,2:2:end),1,[]);

disp(a_1);

  Columns 1 through 37

     1     2     3     4     5     6     7     8     9    10    21    22    23    24    25    26    27    28    29    30    41    42    43    44    45    46    47    48    49    50    61    62    63    64    65    66    67

  Columns 38 through 50

    68    69    70    81    82    83    84    85    86    87    88    89    90

disp(a_0);

  Columns 1 through 37

    11    12    13    14    15    16    17    18    19    20    31    32    33    34    35    36    37    38    39    40    51    52    53    54    55    56    57    58    59    60    71    72    73    74    75    76    77

  Columns 38 through 50

    78    79    80    91    92    93    94    95    96    97    98    99   100

[Ali Albaidhani]

thank you so much

[Voss]

You're welcome!