How to arrange with the graph

2 views (last 30 days)
Emilia
Emilia on 24 Dec 2021
Commented: Emilia on 25 Dec 2021
Hello :)
I need help creating a graph. I wrote in the theta code ranges to be zeros also in the y-axis, and other numbers to get just like this graph.
Thanks in advance
clc;
clear;
K_t=750;
K_r=250;
b=5;
f_z=0.1;
theta=0:360 ;
if theta==60:90 && theta==150:180 && theta==240:270
F_x=0;
F_y=0;
F=0;
else
h_cut=f_z*sin(theta*pi/180);
F_r=K_r*b*h_cut;
F_t=K_t*b*h_cut;
F_x=abs(-F_t.*cos(theta.*pi/180)-F_r.*sin(theta.*pi/180));
F_y=F_t.*sin(theta.*pi/180)-F_r.*cos(theta.*pi/180);
F=sqrt((F_x).^2+(F_y).^2);
plot(theta,F_x,'--r',theta,F_y,'--b',theta,F,'k' )
legend({'F_x' ,'F_y','F'})
end

Accepted Answer

VBBV
VBBV on 25 Dec 2021
clc;
clear;
K_t=750;
K_r=250;
b=5;
f_z=0.1;
theta=0:360 ;
for i = 1: length(theta)
if (theta(i) >= 60 & theta(i) <= 90) || (theta(i) >= 150 & theta(i) <= 180) || (theta(i) >= 240 & theta(i) <= 270)
F_x(i)=0;
F_y(i)=0;
F(i)=0;
else
h_cut=f_z*sin(theta(i)*pi/180);
F_r=K_r*b*h_cut;
F_t=K_t*b*h_cut;
F_x(i)=abs(-F_t.*cos(theta(i).*pi/180)-F_r.*sin(theta(i).*pi/180));
F_y(i)=F_t.*sin(theta(i).*pi/180)-F_r.*cos(theta(i).*pi/180);
F(i)=sqrt((F_x(i)).^2+(F_y(i)).^2);
end
end
plot(theta,F_x,'--r',theta,F_y,'--b',theta,F,'k' )
legend('F_x' ,'F_y','F')

More Answers (0)

Categories

Find more on Programming in Help Center and File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!