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Dimension mismatch error in matlab
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Hi can someone please explain me why the first one is correct and the second one generates error. I am sure it must be something easy but currently I am unable to get it
for i=1:105
x(i,:)=linspace(0,10,41);
end
>> for i=1:105
x(i,:)=linspace(0,10,48);
end
error:Subscripted assignment dimension mismatch.
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Michael Haderlein
on 21 Oct 2014
In the first loop, you either have not yet initialized x or you have initialized it as n-x-41 array. In any case, after the first loop the size of x will be [105 41]. In the second loop, you want to replace the first line of x (which has 41 entries) by an array of 48 elements. That will fail, obviously. How to solve this problem depends on what you want to do. We need a bit more information for that.
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