Repeat Lines 14 to 25 a specified number of times, only print final matrix

I'm really new to matlab. How would I go about getting this to repeat from line 14 to 25 a certain number of times (iterate) for instance 131 times. I don't want it to print the result at each iteration just the resulting matrix after 131 iterations.

clear;
HOLD=zeros(23,23);
HNEW=zeros(23,23);
R=zeros(23,23);
%Initial Value of matrix
for i=1:23
    for j=1:23
        HOLD(i,j)=10
        HNEW(i,j)=10
    end
end
R(22,2)=-0.2;    
%implement implicit method
for i=2:22
    for j=2:22
        H1=0.25*(HOLD(i,j+1)+HOLD(i,j-1)+HOLD(i-1,j)+HOLD(i-1,j-1))
        H2=0.25*(HNEW(i,j+1)+HNEW(i,j-1)+HNEW(i-1,j)+HNEW(i-1,j-1))
        HNEW(i,j)=(1/((100*100*0.002/4/300/0.1)+1))*(H2+100*100*0.002/4/300/0.1*HOLD(i,j)+100*100*R(i,j)/4/300)
    end
end

for i=2:22
    for j=2:22
        HOLD(i,j)=HNEW(i,j)
    end
end
%No Flow Boundarys
for j=1:23
    HOLD(1,:)=HOLD(3,:)
    HOLD(23,:)=HOLD(21,:)
end
for i=1:23
    HOLD(:,1)=HOLD(:,3)
    HOLD(:,23)=HOLD(:,21)
end
%Need to repeat from line 14 a specified number of times.

Answer 1

[Walter Roberson]

for RepeatNumber = 1 : 131
  .... code ...
end

[H]

Thank you. I fixed an error as well. It runs for a very long time though and prints the matrix at every iteration. Is there a way to speed it up and/or only get it to show the final result.

clear;
HOLD=zeros(23,23);
HNEW=zeros(23,23);
R=zeros(23,23);
%Initial Value of matrix
for i=1:23
    for j=1:23
        HOLD(i,j)=10
        HNEW(i,j)=10
    end
end
R(22,2)=-0.2;    
for RepeatNumber = 1 : 3
%implement implicit method
    for i=2:22
        for j=2:22
            H2(i,j)=0.25*(HNEW(i,j+1)+HNEW(i,j-1)+HNEW(i-1,j)+HNEW(i-1,j-1))
            HNEW(i,j)=(1/((100*100*0.002/4/300/0.1)+1))*(H2(i,j)+100*100*0.002/4/300/0.1*HOLD(i,j)+100*100*R(i,j)/4/300)
        end
    end

      for i=2:22
          for j=2:22
              HOLD(i,j)=HNEW(i,j)
          end
      end
  %No Flow Boundarys
      for j=1:23
          HOLD(1,:)=HOLD(3,:)
          HOLD(23,:)=HOLD(21,:)
      end
      for i=1:23
          HOLD(:,1)=HOLD(:,3)
          HOLD(:,23)=HOLD(:,21)
      end
  %Need to repeat from line 14 a specified number of times.
  end

Answer 2

[H]

I'm okay with the iteration thing now, but it takes forever (minutes for three iterations and I need hundreds). It also prints the matrix after every single iteration rather than only after the last one. Is there any way to change that?

clear;
HOLD=zeros(23,23);
HNEW=zeros(23,23);
R=zeros(23,23);
%Initial Value of matrix
for i=1:23
    for j=1:23
        HOLD(i,j)=10
        HNEW(i,j)=10
    end
end
R(22,2)=-0.2;    
for RepeatNumber = 1 : 3
%implement implicit method
    for i=2:22
        for j=2:22
            H2(i,j)=0.25*(HNEW(i,j+1)+HNEW(i,j-1)+HNEW(i-1,j)+HNEW(i-1,j-1))
            HNEW(i,j)=(1/((100*100*0.002/4/300/0.1)+1))*(H2(i,j)+100*100*0.002/4/300/0.1*HOLD(i,j)+100*100*R(i,j)/4/300)
        end
    end
      for i=2:22
          for j=2:22
              HOLD(i,j)=HNEW(i,j)
          end
      end
  %No Flow Boundarys
      for j=1:23
          HOLD(1,:)=HOLD(3,:)
          HOLD(23,:)=HOLD(21,:)
      end
      for i=1:23
          HOLD(:,1)=HOLD(:,3)
          HOLD(:,23)=HOLD(:,21)
      end
  %Need to repeat from line 14 a specified number of times.
  end

[Walter Roberson]

semi-colon on the end of a line prevents the result of the assignment from being displayed. For example instead of

HOLD(i,j)=HNEW(i,j)

use

HOLD(i,j)=HNEW(i,j);