how to initialize a vector of structure
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hello
so i have the example abouve
for i = 1 : n
structure.a = .......
structure.b = .......
.
.
structure.z = .......
my_vector(i) = structure;
end
the question is how i can preallocte the space size for the vector my_vector ?
thanks in advance
1 Comment
James Tursa
on 4 Mar 2014
What is the stuff on the right-hand-side? Are you attempting to just get my_vector pre-allocated to hold the correct fields but not actually have anything in the field elements?
Answers (4)
Kan-Hua
on 4 Mar 2014
To preallocate memory, you need to put some values into the data structure that you are using. I think it's the design of Matlab. For example, to preallocate a memory for a 25x25 matrix, you need
mtx=zeros(25)
or
mtx=ones(25)
It is the same case for a structure array. To preallocate the memory space, you have to put some dummy values into every fields of the structure.
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Jos (10584)
on 4 Mar 2014
Edited: Jos (10584)
on 4 Mar 2014
As Mischa pointed out: preallocation of structures is easy:
S(1:5) = struct('a',zeros(10,1),'b','empty')
2 Comments
Jos (10584)
on 4 Mar 2014
If your fieldnames are known and you all want to set them to the same default value, in a 1-by-N array of structures S , try this
fn = {'a','b','c','d'} ; % this can be coded as well ...
value = zeros(1,10) ;
N=5 ;
S(1:N) = cell2struct(repmat({value},numel(fn),1),fn,1)
Kan-Hua
on 4 Mar 2014
You can consider using table instead of structure array to store your data, which gives some flexibility to access the members. However, the version of you Matlab has to be 2013b or later.
Here's some example code of using table, which may solve your problem:
% initialise a table
zarray=zeros(1,3);
T=array2table(zarray,'VariableNames',{'colA','colB','colC'});
%show the initial values of the array
disp(T);
% assign the first row of the table by using names
T.colA(1)=1;
T.colB(1)=2;
T.colC(1)=3;
%Print out the table
disp(T);
% Alternatively, you can do it by index
for i=1:size(T,2)
T(2,i)={i*2};
end
% Print out the table
disp(T)
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