Generating integer random numbers from power-law distribution

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Is there a code to generate integer random numbers through power-law distribution of the form p(x)=x^-(alpha+1)?
thanks in advance

Accepted Answer

Image Analyst
Image Analyst on 13 Dec 2013
Try this: RANDRAW

More Answers (3)

Miguel Ángel
Miguel Ángel on 13 Dec 2013
Edited: Miguel Ángel on 13 Dec 2013
I don't know if round,ceil or floor is correct, but in case this may be a way
n=1000;
p=rand(1,n);
alpha=0.1;
%inverse of distribution
%properties of logs %LOGa(n) = LOGb(N) / LOGb(a)
%~round/ceil/floor
x=round(log(p)/log(alpha+1));
  1 Comment
Sunstar
Sunstar on 13 Dec 2013
Thank you for your reply. Unfortunately, I cannot simply round or floor or ceil. I need to generate real integers.

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Roger Stafford
Roger Stafford on 13 Dec 2013
The distribution you mention is equivalent to the zeta distribution with alpha+1 replaced by s. See the website
http://en.wikipedia.org/wiki/Zeta_distribution
As Image Analyst has mentioned, there is a File Exchange contribution called 'randraw' which is located at:
http://www.mathworks.com/matlabcentral/fileexchange/7309-randraw
which claims to generate random numbers in accordance with fifty various distributions including the zeta distribution. It might be what you need.

Weijia Chen
Weijia Chen on 18 Sep 2019
I also meet the same problem. The minimum integer that zeta distribution can generate seems to be 1, but I hope 0 can be generated. Is there any other distributin can do this? Thank you

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