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Problem with a slope

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as hz
as hz on 27 Oct 2013
Commented: Image Analyst on 27 Oct 2013
Hi,
Why does the slope result I get from these two points is opposite?
Code:
clc;
clear;
figure, imshow('pout.tif');
b1 = impoint(gca,[]);
b2 = impoint(gca,[]);
pos1 = getPosition(b1);
x1=pos1(1,1);
y1=pos1(1,2);
pos2 = getPosition(b2);
x2=pos2(1,1);
y2=pos2(1,2);
slope = (y2-y1)/(x2-x1);
plot([x1,x2 ],[y1,y2],'Color','r','LineWidth',2);

Accepted Answer

Azzi Abdelmalek
Azzi Abdelmalek on 27 Oct 2013
Maybe you should write
slope = ((y1-y2)/(x2-x1))
You can notice that the origin is not in the left bottom, but in the left top corner. check it with
x1
x2
y1
y2
  1 Comment
Image Analyst
Image Analyst on 27 Oct 2013
The direction can be changed with set(gca,'YDir','reverse'). Or maybe it already is since that's what imshow does. In that case, try set(gca,'YDir','normal').

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