Cody

Problem 9. Who Has the Most Change?

Solution 1801999

Submitted on 1 May 2019 by CHUANQIANG ZHANG
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Test Suite

Test Status Code Input and Output
1   Pass
a = [1 2 1 15]; b = 1; assert(isequal(most_change(a),b))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0.2500 2.0000 1.0000 15.0000 a = 0.2500 0.1000 1.0000 15.0000 a = 0.2500 0.1000 0.1000 15.0000 a = 0.2500 0.1000 0.1000 0.1500 dim = 1 4 overview = 0.6000 rich = 0.6000 output = 1

2   Pass
a = [ 1 2 1 15; 0 8 5 9]; b = 2; assert(isequal(most_change(a),b))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0.2500 2.0000 1.0000 15.0000 0 8.0000 5.0000 9.0000 a = 0.2500 0.1000 1.0000 15.0000 0 0.4000 5.0000 9.0000 a = 0.2500 0.1000 0.1000 15.0000 0 0.4000 0.5000 9.0000 a = 0.2500 0.1000 0.1000 0.1500 0 0.4000 0.5000 0.0900 dim = 2 4 overview = 0.6000 0.9900 rich = 0.9900 output = 2

3   Pass
a = [ 1 22 1 15; 12 3 13 7; 10 8 23 99]; b = 3; assert(isequal(most_change(a),b))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0.2500 22.0000 1.0000 15.0000 3.0000 3.0000 13.0000 7.0000 2.5000 8.0000 23.0000 99.0000 a = 0.2500 1.1000 1.0000 15.0000 3.0000 0.1500 13.0000 7.0000 2.5000 0.4000 23.0000 99.0000 a = 0.2500 1.1000 0.1000 15.0000 3.0000 0.1500 1.3000 7.0000 2.5000 0.4000 2.3000 99.0000 a = 0.2500 1.1000 0.1000 0.1500 3.0000 0.1500 1.3000 0.0700 2.5000 0.4000 2.3000 0.9900 dim = 3 4 overview = 1.6000 4.5200 6.1900 rich = 6.1900 output = 3

4   Pass
a = [ 1 0 0 0; 0 0 0 24]; b = 1; assert(isequal(most_change(a),b))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0.2500 0 0 0 0 0 0 24.0000 a = 0.2500 0 0 0 0 0 0 24.0000 a = 0.2500 0 0 0 0 0 0 24.0000 a = 0.2500 0 0 0 0 0 0 0.2400 dim = 2 4 overview = 0.2500 0.2400 rich = 0.2500 output = 1

5   Pass
a = [ 0 1 2 1; 0 2 1 1]; c = 1; assert(isequal(most_change(a),c))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0 1 2 1 0 2 1 1 a = 0 0.0500 2.0000 1.0000 0 0.1000 1.0000 1.0000 a = 0 0.0500 0.2000 1.0000 0 0.1000 0.1000 1.0000 a = 0 0.0500 0.2000 0.0100 0 0.1000 0.1000 0.0100 dim = 2 4 overview = 0.2600 0.2100 rich = 0.2600 output = 1

6   Pass
% There is a lot of confusion about this problem. Watch this. a = [0 1 0 0; 0 0 1 0]; c = 2; assert(isequal(most_change(a),c)) % Now go back and read the problem description carefully.

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0 1 0 0 0 0 1 0 a = 0 0.0500 0 0 0 0 1.0000 0 a = 0 0.0500 0 0 0 0 0.1000 0 a = 0 0.0500 0 0 0 0 0.1000 0 dim = 2 4 overview = 0.0500 0.1000 rich = 0.1000 output = 2

7   Pass
a = [ 2 1 1 1; 1 2 1 1; 1 1 2 1; 1 1 1 2; 4 0 0 0]; c = 5; assert(isequal(most_change(a),c))

quarter = 0.2500 dime = 0.1000 nickel = 0.0500 penny = 0.0100 a = 0.5000 1.0000 1.0000 1.0000 0.2500 2.0000 1.0000 1.0000 0.2500 1.0000 2.0000 1.0000 0.2500 1.0000 1.0000 2.0000 1.0000 0 0 0 a = 0.5000 0.0500 1.0000 1.0000 0.2500 0.1000 1.0000 1.0000 0.2500 0.0500 2.0000 1.0000 0.2500 0.0500 1.0000 2.0000 1.0000 0 0 0 a = 0.5000 0.0500 0.1000 1.0000 0.2500 0.1000 0.1000 1.0000 0.2500 0.0500 0.2000 1.0000 0.2500 0.0500 0.1000 2.0000 1.0000 0 0 0 a = 0.5000 0.0500 0.1000 0.0100 0.2500 0.1000 0.1000 0.0100 0.2500 0.0500 0.2000 0.0100 0.2500 0.0500 0.1000 0.0200 1.0000 0 0 0 dim = 5 4 overview = 0.6600 0.4600 0.5100 0.4200 1.0000 rich = 1 output = 5

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