Cody

# Problem 36. Find relatively common elements in matrix rows

Solution 2172986

Submitted on 24 Mar 2020 by Austin Lodish
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### Test Suite

Test Status Code Input and Output
1   Pass
x = []; y_correct = []; assert(isequal(common_by_row(x),y_correct))

2   Pass
x = [1e100; 1e100]; y_correct = [1e100]; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 2 y = 1.0000e+100

3   Pass
x = [1; 2]; y_correct = []; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 1

4   Pass
x = ones(10); y_correct = [1]; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 2 k = 3 k = 4 k = 5 k = 6 y = 1

5   Pass
x = magic(10); y_correct = []; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1 k = 1

6   Pass
x = wilkinson(9); y_correct = [0 1]; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 2 k = 3 k = 4 k = 5 y = 0 k = 1 k = 2 k = 3 k = 4 k = 5 y = 0 1 k = 1 k = 2 k = 1 k = 2 k = 1 k = 2

7   Pass
x = [3 -2 1 NaN; NaN 0 -2 3]; y_correct = [-2 3]; assert(isequal(common_by_row(x),y_correct))

k = 1 k = 2 y = -2 k = 1 k = 1 k = 1 k = 2 y = -2 3