Cody

# Problem 32. Most nonzero elements in row

Solution 209267

Submitted on 27 Feb 2013 by Shaun VanWeelden
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### Test Suite

Test Status Code Input and Output
1   Pass
%% a = [ ... 1 2 0 0 0 0 0 5 0 0 2 7 0 0 0 0 6 9 3 3]; r_correct = 4; assert(isequal(fullest_row(a),r_correct))

a = 1 2 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 2 7 0 0 0 0 0 0 0 0 0 6 9 3 3 0 0 0 0 0 r = 1 1 0 0 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 1 1 1 1 0 0 0 0 0 max2 = 4 r = 4

2   Pass
%% a = [ ... 1 2 0 0 0 0 5 0 0 6 9 -3 2 7 0 0 0 0 0 0]; r_correct = 3; assert(isequal(fullest_row(a),r_correct))

a = 1 2 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 6 9 -3 0 0 0 0 2 7 0 0 0 0 0 0 0 0 0 0 0 0 0 0 r = 1 1 0 0 0 0 0 0 0 0 1 0 0 0 0 0 0 1 1 1 0 0 0 0 1 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 max2 = 3 r = 3

3   Pass
%% a = [ ... 1 0 0 0 0 0 0 0 0 0 0 0 0 2 3]; r_correct = 5; assert(isequal(fullest_row(a),r_correct))

a = 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2 3 0 0 0 r = 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1 1 0 0 0 max2 = 2 r = 5

4   Pass
%% a = [ ... 0 0 0 -3 0 0]; r_correct = 4; assert(isequal(fullest_row(a),r_correct))

a = 0 0 0 0 0 0 -3 0 0 0 0 0 r = 0 0 0 0 0 0 1 0 0 0 0 0 max2 = 1 r = 4