The problem is pretty stupid, if there's only one test case. Then you can just return the correct result for this test case, without really computing anything (which is what the "best" solution to this problem does.
Flip the main diagonal of a matrix
Put two time series onto the same time basis
Implement simple rotation cypher
Get the elements of diagonal and antidiagonal for any m-by-n matrix
Create an n-by-n null matrix and fill with ones certain positions
Duplicate each element of a vector.
A quadrant matrix
Remove NaN ?
Matrix which contains the values of an other matrix A at the given locations.
vectorization in N
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