Cody

Problem 1024. Doubling elements in a vector

Solution 2256247

Submitted on 5 May 2020 by MDK
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Test Suite

Test Status Code Input and Output
1   Pass
x = 1; y_correct = [1 1]; assert(isequal(your_fcn_name(x),y_correct))

Acnt = 1 Bcnt = 1 B = 1 0 B = 1 1 Acnt = 2 Bcnt = 3

2   Pass
x = [0 -1 1 0 0 0 1 2]; y_correct = [0 0 -1 -1 1 1 0 0 0 0 0 0 1 1 2 2]; assert(isequal(your_fcn_name(x),y_correct))

Acnt = 1 Bcnt = 1 B = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 B = 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 Acnt = 2 Bcnt = 3 B = 0 0 -1 0 0 0 0 0 0 0 0 0 0 0 0 0 B = 0 0 -1 -1 0 0 0 0 0 0 0 0 0 0 0 0 Acnt = 3 Bcnt = 5 B = 0 0 -1 -1 1 0 0 0 0 0 0 0 0 0 0 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 Acnt = 4 Bcnt = 7 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 Acnt = 5 Bcnt = 9 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 Acnt = 6 Bcnt = 11 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 0 0 0 0 Acnt = 7 Bcnt = 13 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 1 0 0 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 1 1 0 0 Acnt = 8 Bcnt = 15 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 1 1 2 0 B = 0 0 -1 -1 1 1 0 0 0 0 0 0 1 1 2 2 Acnt = 9 Bcnt = 17

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