# Why do I receive the error "Attempt to execute SCRIPT FILENAME as a function"?

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I receive the error:

??? Attempt to execute SCRIPT untitled as a function.

### Accepted Answer

MathWorks Support Team
on 14 Oct 2013

Edited: MathWorks Support Team
on 12 Feb 2018

This error results because there is a MATLAB script named [filename] and your calling syntax requires that this script either takes arguments or returns values, which are properties of a function and not of a script. For example, if you have a script called 'banana.m' containing:

disp('banana');

and you call the script with two input arguments as though it were a function by typing the following at the Command Prompt:

banana(1,1)

Then you will get the error. To call the script without error, try calling the script without arguments:

banana

Second, the error can happen because there is a script [filename] and a function [filename] that both exist on the path. If the script appears before the function on the path, then your commands will attempt to use it instead of the function. In Release 2006b (R2006b) and newer versions of MATLAB, the error message will display the location of the script that is called. Rename this script to a more appropriate name. For previous product releases you may use the command:

which <filename>

to determine which instance of [filename] that MATLAB is attempting to call. If you want to see all instances of a function on the path, type the command:

which <filename> -all

Alternatively, such behavior may occur in certain scenarios where your filename contains invalid characters. In particular, you may see this error if the filename contains characters that are MATLAB operators such as -, +, or *. MATLAB filenames must begin with a letter, which may be followed by any combination of letters, digits, and underscores.

##### 9 Comments

Walter Roberson
on 13 Aug 2020

### More Answers (16)

Lode
on 24 Jan 2016

Maybe a stupid remark, but it took me 1h to find...

run(filename.m) doesn't work. You should use run('filename.m') if you didn't put the filename in a variable. This is a very basic mistake but maybe useful to somebody...

##### 3 Comments

Bruce Lin
on 2 Nov 2015

As mentioned in my comment to JMS above, there is a different way you can get this error which the Mathworks respondents did not cover.

If you have a script called ABC.m and a script called ABC-copy.m, and try to run ABC-copy, it will fail with the error above "Attempt to execute SCRIPT FILENAME as a function"

MATLAB interprets the minus sign as an operator, not part of a filename, and the fact that you ALSO have a script called "ABC.m" means that MATLAB tries to execute

"ABC.m - copy.m"

You can prove this by temporarily deleting ABC.m and running 'ABC-copy'. You will see that you get a file not found error instead where MATLAB cannot find ABC.m

One would think that this could be corrected by executing 'ABC-copy.m', i.e. explicitly specifying the .m extension, but it doesn't fix the problem for me.

Hope this helps someone in the future.

##### 4 Comments

Walter Roberson
on 4 May 2015

Edited: MathWorks Support Team
on 30 Dec 2021

In addition:

As a practical matter, when basic built-in routines such as disp() are the ones being mentioned as scripts, the problem is almost always that the installation is corrupt for any of several reasons, and reinstallation is required.

A lesser possibility is that the installation is okay but the user has managed to set the MATLAB path to include library directories that should not be named directly, such as if the documentation directory has been added to the MATLAB path. In such cases, restoredefaultpath can be used.

##### 0 Comments

Hugo Pontes
on 14 May 2020

I'm just answering so that if anyone faces the same problem I did it'll easier to correct.

If you download the same .m file twice to windows it will automatically name it filename(1).m . If you try to run that file with the (1) MATLAB will assume it's a function and that error will prompt. It sounds silly but yes just change the file name!

##### 0 Comments

Ivan Dwi Putra
on 27 Nov 2019

I can't execute the lqr function

close all

% Initial Conditions

x0 = [3; % 3 radians

0]; % 0 rad/s

% System Dynamics

A = [0 1;

0.01 0];

B = [0;

1];

C = [1 0];

D = 0;

% Control Law

Q = [1 0; % Penalize angular error

0 1]; % Penalize angular rate

R = 1; % Penalize thruster effort

K = lqr(A,B,Q,R);

% Closed loop system

sys = ss((A - B*K), B, C, D);

% Run response to initial condition

t = 0:0.005:30;

[y,t,x] = initial(sys, x0, t);

##### 0 Comments

ismet iris
on 24 May 2020

comPort = 'COM7';

if (~exist('serialFlag','var'))

[arduino.s,serialFlag]=setupSerial(comPort);

end

if(~exist('h','var') || ~ishandle(h))

h=figure(1);

end

if(~exist('text1','var'))

text1=uicontrol('Style','Text','String','X: 0 degrees',...

'pos',[450 100 100 25],'parent',h);

end

if(~exist('text2','var'))

text2=uicontrol('Style','Text','String','Y: 0 degrees',...

'pos',[450 75 100 25],'parent',h);

end

if(~exist('button','var'))

button=uicontrol('Style','togglebutton','String','Stop & Close Serial Port',...

'pos',[0 0 200 25],'parent',h);

end

weights = [ 0 20 50 70 100 120 150 170 200 220 250];

m = zeros(length(weights),1);

for i = 2:length(weights)

mbox=msgbox(['Place' num2str(weights(i)) ' grams on thr FSR']); uiwait(mbox);

m(i)=readFSR(fsr);

while(m(i) < m(i-1)) || m(i) ==0

m(i) = readFSR(fsr);

end

end

p1=polyfit(m,weights,2);

myaxes=axes('xlim',[-20 20], 'ylim', [-20 20],'zlim',[-0 250]);

view(3);

grid on;

axis equal;

hold on;

[xsphere, ysphere, zsphere]=sphere();

h(1)=surface(xsphere, ysphere, zsphere);

combinedobject = hgtransform('parent',myaxes);

set(h, 'parent',combineobject)

drawnow;

while (get(button, 'value')==0)

[voltage]=readFSR(fsr);

mass = polyval(p1, voltage);

if (mass>0)

force=mass*9.81;

set(text1,'String',['Mass :' num2str(round(mass)) 'grams'])

set(text2,'String',['Force :' num2str(round(force)) 'N'])

translation = makehgtform('translate',[0 0 mass]);

set(combinedobject,'matrix',translation);

scaling=makehgtform('scale',mass/10);

set(combinedobject,'matrix',scaling);

set(combinedobject, 'natrix',translation*scaling);

end

pause(0.1);

end

closeSerial;

WHY THİS ERROR ?

Attempt to execute SCRIPT fsr as a function:

C:\Users\ismet\Desktop\fsr.m

Error in fsr (line 28)

m(i)=readFSR(fsr);

##### 1 Comment

Walter Roberson
on 13 Jun 2020

Anish Gunjal
on 4 Jul 2020

##### 0 Comments

ahsan meo
on 22 Nov 2020

Edited: Walter Roberson
on 3 Jul 2021

clc

close all

clear all

x=[1 2 3];

y=[4 5 6];

c=polyfit(x,y,2)

this error will be come

Attempt to execute SCRIPT polyfit as a function:

D:\NC codes\polyfit.m

Error in vander (line 6)

c=polyfit(x,y,2)

>>

##### 1 Comment

Steven Lord
on 22 Nov 2020

ahsan meo
on 25 Nov 2020

clc

close all

clear all

x =[-2, -1, 2];

A = vander([-2, -1, 2]);

y = [-2 1 -1]';

c = A\y

these errors are come

Attempt to execute SCRIPT vander as a function:

D:\NC codes\vander.m

Error in Untitled111 (line 5)

A = vander([-2, -1, 2]);

##### 4 Comments

Steven Lord
on 4 Jan 2021

Ritu Roy Chowdhury
on 16 Mar 2021

Hello,

Also make sure that the name of the script doesn't include hyphens (-), and other illegal characters.

Best

##### 0 Comments

madhuri parimi
on 29 Jun 2021

n=1000;

p=[];

for i=1:n

phase(i)=(pi/n)*(i-1)*(i-n-1);

end

for k=1:1000;

y(k)=sqrt(cos(phase(k)^2)+(sin(phase(k)^2)));

end

x1 autocorr = autocorr(y);

x1=x1 autocorr^2;

x2=max( x1 autocorr);

s=0;

for i=1:20

s=s+((x1 autocorr(i)^2)/(x2^2));

end

islr=10*log10(s/150)

for j=5:20

x4=(x1 autocorr(j));

end

pslr=20*log10(0.3020/(3*x2))

it is showig error in autocorr function can u help me with that?

##### 4 Comments

Walter Roberson
on 29 Jun 2021

madhuri parimi
on 30 Jun 2021

n=1000;

p=[];

for i=1:n

for j=1:n

phase(i)=(pi/2*n)*(n-2*i+1)*(n-2*j+1);

end

end

for k=1:1000

for l=1:1000

y(k)=sqrt(cos(phase(k)^2)+(sin(phase(k)^2)));

end

end

M = 20;

R = zeros(M+1, 1);

for n=0:M

for k=0:n-1

R(n+1) = R(n+1) + y(k+1) * y(k+n+1);

end

end

x1autocorr = R(n+1);

x1=x1autocorr^2;

x2=max(x1autocorr);

s=0;

for i=1:20

s=s+((x1autocorr(i)^2)/(x2^2));

end

islr=10*log10(s/150)

for j=5:20

x4=(x1autocorr(j));

end

pslr=20*log10(0.3020/(3*x2))

error:

Index exceeds the number of array elements (1).

Error in final (line 25)

s=s+((x1autocorr(i)^2)/(x2^2));

help me to rectify it

##### 1 Comment

Walter Roberson
on 30 Jun 2021

n=1000;

p=[];

for i=1:n

for j=1:n

phase(i)=(pi/2*n)*(n-2*i+1)*(n-2*j+1);

end

end

for k=1:1000

for l=1:1000

y(k)=sqrt(cos(phase(k)^2)+(sin(phase(k)^2)));

end

end

M = 20;

R = zeros(M+1, 1);

for n=0:M

for k=0:n-1

R(n+1) = R(n+1) + y(k+1) * y(k+n+1);

end

end

R is a vector at this point

x1autocorr = R(n+1);

Here you are using the "left-over" value of n from the for n loop when you do the indexing. The last value assigned to n is going to be M so after the for n loop, n is going to equal M, So R(n+1) is going to be R(M+1) . If that is your intention, then code R(M+1) so that people do not get confused about which part of R is being accessed.

n is going to be a scalar after the loop. It is not uncommon for people to expect that after a for loop, that the loop control variable will be a vector (or array) of all of the values the loop control variable was assigned, but that simply is not the case: after the loop it will just be the last value. So R(n+1) is going to be a scalar, so x1autocorr() is going to be a scalar.

x1=x1autocorr^2;

That line assumes that x1autocorr is a scalar (or a square matrix)

x2=max(x1autocorr);

max() of a scalar is the value of the scalar.

size(x1autocorr)

s=0;

for i=1:20

s=s+((x1autocorr(i)^2)/(x2^2));

end

You are trying to access x1autocorr(i) but x1autocorr is a scalar.

islr=10*log10(s/150)

for j=5:20

x4=(x1autocorr(j));

end

You overwrite all of x4 each iteration of that for j loop. What is the point of doing that?

pslr=20*log10(0.3020/(3*x2))

You ignore the x4 you just created, and you use x2, but x2 is not defined.

madhuri parimi
on 3 Jul 2021

Edited: Walter Roberson
on 3 Jul 2021

n=1000;

p=[];

for i=1:n

phase(i)=(pi/n)(i-1)(i-n-1);

end

for k=1:1000;

y(k)=sqrt(cos(phase(k)^2)+(sin(phase(k)^2)));

end

x1autocorr = autocorr(y);

x1=x1autocorr.^2;

x2=max(x1autocorr);

s=0;

for i=1:20

s=s+((x1autocorr(i)^2)/(x2^2));

end

islr=10*log10(s/150)

for j=5:20

x4=(x1autocorr(j));

end

pslr=20*log10(0.3020/(3*x2))

error:

Attempt to execute SCRIPT error

as a function:

C:\Matlab\Matlab 2016a\Matlab

2016a\Matlab 2016a Win64

Crack\bin\error.m

Error in autocorr (line 83)

error(message('econ:autocorr:NonVectorInput'))

Error in Untitled (line 9)

x1autocorr = (autocorr(y));

help me to rectify

##### 1 Comment

Muhammad Deeb
on 6 Nov 2021

I try to apply Wavelet conversion but I always get this error:

Execution of script dwt as a function is not supported

how i can solve this problem

##### 1 Comment

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