# polyval error with recurrence relation

4 views (last 30 days)
T on 6 Oct 2013
Commented: T on 11 Oct 2013
function c = relation( n )
if n==0
c = 1;
elseif n==1
syms x
c = [x 0];
else
syms x
c = ((2*n-1)*x*[relation(n-1),0] - (n-1)*[0,0,relation(n-2)])/n;
sum(c)
end
n=8
m=n+1;
xval=linspace(-1,1,5000)
I=trapsum(polyval(relation(n),xval).*polyval(relation(m),xval),-1,1);
Gives the following output:
??? Error using ==> polyval
Inputs to polyval must be floats, namely single or double.
Error in ==> polyval at 63
y = zeros(siz_x, superiorfloat(x,p));
What needs to be done to ensure that the output for the recurrence relation is a double?
I mean, in the function, we have syms x but this is to acquire the polynomial in analytic form. It's not necessary in this case but I need to plot it later on. The main issue I have is evaluating the integral using trapsum but I would need to do both; plot for various n, evaluate the integral.
##### 0 CommentsShow -2 older commentsHide -2 older comments

Sign in to comment.

### Accepted Answer

Walter Roberson on 6 Oct 2013
In your code for relation(), why do you have
sum(c)
which is just displaying the sum rather than returning the sum ?
After you build the relation symbolically, use
RelationM = relation(m);
RelationN = relation(n);
funM = matlabFunction(RelationM);
funN = matlabFunction(RelationN);
Y = funM(xval) .* funN(xval);
trapsum(Y, -1, 1)
However, I do not know what your trapsum routine does: it is not a routine in any Mathworks toolbox, and the obvious trapsum in the File Exchange uses a different calling sequence.
##### 14 CommentsShow 12 older commentsHide 12 older comments
T on 8 Oct 2013
That's right. And for some reason using c1 and c2 will not generate the same polynomials for n where if you used
c = ((2*n-1)*x*[relation(n-1),0] - (n-1)*[0,0,relation(n-2)])/n;
The point was to do this using recursive programming.
T on 11 Oct 2013
Edited: T on 11 Oct 2013
Actually I don't think I need to do any of the above:
for n=0:inf
m=n+1;
int( ((2*n-1)*x*[relation(n-1),0] - (n-1)*[0,0,relation(n-2)])/n )* ((2*m-1)*x*[relation(m-1),0] - (m-1)*[0,0,relation(m-2)])/m),x,-1,1)
end
This will just give me zero. But is it possible to determine the round-off error? Or at least get the maximum value of n before the loop crashes?
I can set the recursion limit using:
set(0, 'RecursionLimit', 100000) but it keeps crashing still.

Sign in to comment.

### More Answers (1)

Matt J on 6 Oct 2013
Edited: Matt J on 6 Oct 2013
Get rid of the "syms x". You are doing only numerical manipulations with the polynomial so there is no apparent need to have it in symbolic form, and that includes for plotting. Example
t=linspace(-1,1,1000);
p=[1 2 1]; %polynomial coefficients
plot(t,polyval(p,t))
Also, why use trapsum instead of the builtin trapz?
##### 3 CommentsShow 1 older commentHide 1 older comment
Matt J on 6 Oct 2013
It's the function relation() that can't be found. Check your path.
T on 6 Oct 2013
Okay now I receive the error:
??? Undefined function or variable 'x'.
Error in ==> rlegendre at 9
c = ((2*n-1)*x*[rlegendre(n-1),0] - (n-1)*[0,0,rlegendre(n-2)])/n;
This happens when I remove syms x.

Sign in to comment.

### Categories

Find more on Common Operations in Help Center and File Exchange

### Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!