# Findd non nun values indexes in every row of a matrix

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GSM on 29 Jul 2021
Answered: DGM on 29 Jul 2021
Hello,
How can I find the NaN or the non-Nan indexes for every row in a matrix.
For example in the following matrix:
a =
1 1 1 NaN 1 1 1 1 1 1
2 2 2 2 NaN 2 2 2 2 2
3 3 3 3 3 NaN 3 NaN 3 3
I'd like to have the follwing answer for the NaN indexes in every row:
a1=4, a2=5, a3=[6,8]
Also, how can I store the indexes seperately for each row in case I have different number of values per row? What is the best way? A row-vector which nubmer of cells equivalent to the number of rows in the a-matrix, where each cell of the row_vectors stors the answer for each row?

DGM on 29 Jul 2021
You could do this:
A = [1 1 1 NaN 1 1 1 1 1 1
2 2 2 2 NaN 2 2 2 2 2
3 3 3 3 3 NaN 3 NaN 3 3];
C = num2cell(isnan(A),2);
C = cellfun(@find,C,'uniform',false)
C = 3×1 cell array
{[ 4]} {[ 5]} {[6 8]}
Or depending on how you intend to use the result, you could probably just get the logical mask from isnan(A) and use its rows directly without needing to deal with find() and variable-length index vectors.

R2020b

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