# Why my vars become to NaN?

1 view (last 30 days)
Tony Castillo on 18 Dec 2020
Commented: Tony Castillo on 18 Dec 2020
Dear Coders,
I have been testing the following code section by section and at first glance it worked properly, but when I have tested the code to plot only one curve per month, so that twelve curves, the vars ME2 and ME3 accumulate NaN values. Why this problem arises?
"REE_perfiles2020
Array indices must be positive integers or logical values.
Error in REE_perfiles2020 (line 174)
plot([ME(1i)])"
REE(744); %%%%V
NDias=REE(:,1); %%%%%
%%%%
aP=REE(:,4); %
ai=reshape(aP,[24, 366]); %%%%%
%
for NDias=1:length(NDias)
%
if NDias==1
[row1, col]=find(NDias==1);
dEne=length(row1)/24; %%%
E=ai(:,(1:31));
ME=mean(E,2);
elseif NDias==2
[row2, col]=find(NDias==2);
dFeb=length(row2)/24;
ld2=row2/24;
logFeb=max(ld2)-dFeb;
E2=ai(:,((max(ld2)-dFeb)+1:max(ld2)));
ME2=mean(E2,2);
elseif NDias==3
[row3, col]=find(NDias==3);
dMar=length(row3)/24;
ld3=row3/24;
logMar=max(ld3)-dMar;
E3=ai(:,((round(ld3)-dMar)+1:max(ld3)));
ME3=mean(E3,2);
elseif NDias==4
[row4, col]=find(NDias==4);
dAbr=length(row4)/24;
ld4=row4/24;
logAbr=max(ld4)-dAbr;
E4=ai(:,(round(logAbr):max(ld4)));
ME4=mean(E4,2);
elseif NDias==5
[row5, col]=find(NDias==5);
dMay=length(row5)/24;
ld5=row5/24;
logMay=max(ld5)-dMay;
E5=ai(:,((round(ld5)-dMay)+1:max(ld5)));
ME5=mean(E5,2);
elseif NDias==6
[row6, col]=find(NDias==6);
dJun=length(row6)/24;
ld6=row6/24;
logJun=max(ld6)-dJun;
E6=ai(:,((round(ld6)-dJun)+1:max(ld6)));
ME6=mean(E6,2);
elseif NDias==7
[row7, col]=find(NDias==7);
dJul=length(row7)/24;
ld7=row7/24;
logJul=max(ld7)-dJul;
E7=ai(:,((round(ld7)-dJul)+1:max(ld7)));
ME7=mean(E7,2);
elseif NDias==8
[row8, col]=find(NDias==8);
dAgo=length(row8)/24;
ld8=row8/24;
logAgo=max(ld8)-dAgo;
E8=ai(:,((round(ld8)-dAgo)+1:max(ld8)));
ME8=mean(E8,2);
elseif NDias==9
[row9, col]=find(NDias==9);
dSep=length(row9)/24;
ld9=row9/24;
logSep=max(ld9)-dSep;
E9=ai(:,((round(ld9)-dSep)+1:max(ld9)));
ME9=mean(E9,2);
elseif NDias==10
[row10, col]=find(NDias==10);
dOct=round(length(row10)/24);
ld10=row10/24;
logOct=max(ld10)-dOct;
E10=ai(:,(((round(logOct)-dOct)+1:max(ld10))));
ME10=mean(E10,2);
elseif NDias==11
[row11, col]=find(NDias==11);
dNov=length(row11)/24;
ld11=row11/24;
logNov=max(ld11)-dNov;
E11=ai(:,(((round(logNov)-dNov)+1:max(ld11))));
ME11=mean(E11,2);
else
[row12, col]=find(NDias==12); %%%l
dDic=length(row12)/24; %%%%
ld=row12/24;
logDic=max(ld)-dDic;
E12=ai(:,((max(ld)-dDic)+1:max(ld)));
ME12=mean(E12,2);
end
plot(ME(1i))
hold on
end

KALYAN ACHARJYA on 18 Dec 2020
Edited: KALYAN ACHARJYA on 18 Dec 2020
Here
plot(ME(1i))
M(1i) what does it means? 1i is a complex number for MATLAB
>> 1i
ans =
0.0000 + 1.0000i
MATLAB allows positive integer indexing only. More. Before plot ME in each iteration, ensure that ME return as a vector. Note: There is no ME variable in elseif condition.It seems that the code needs some modification.
##### 1 CommentShowHide None
Tony Castillo on 18 Dec 2020
I think I undertood your recommendation, but I still has some bug here in my new code, becuase of this error:
Index in position 2 is invalid. Array indices must be positive integers or logical
values.
Error in REE_perfiles2020 (line 48)
E4=ai(:,(round(logAbr):max(ld4)));
%%%%%carg
REE(744); %%%%Ver
NDias=REE(:,1); %%%%%
aP=REE(:,4); %%%%Ext
ai=reshape(aP,[24, 366]); %%%
ME_=zeros(24,12);
%
for NDias=1:length(NDias)
%
%%%%se cargan los perfiles de consum
if NDias==1
[row1, col]=find(NDias==1); %
dEne=length(row1)/24; %
E=ai(:,(1:31));
ME=mean(E,2);
elseif NDias==2
[row2, col]=find(NDias==2);
dFeb=length(row2)/24;
ld2=row2/24;
logFeb=max(ld2)-dFeb;
E2=ai(:,((max(ld2)-dFeb)+1:max(ld2)));
ME=mean(E2,2);
elseif NDias==3
[row3, col]=find(NDias==3);
dMar=length(row3)/24;
ld3=row3/24;
logMar=max(ld3)-dMar;
E3=ai(:,((round(ld3)-dMar)+1:max(ld3)));
ME=mean(E3,2);
elseif NDias==4
[row4, col]=find(NDias==4);
dAbr=length(row4)/24;
ld4=row4/24;
logAbr=max(ld4)-dAbr;
E4=ai(:,(round(logAbr):max(ld4)));
ME=mean(E4,2);
elseif NDias==5
[row5, col]=find(NDias==5);
dMay=length(row5)/24;
ld5=row5/24;
logMay=max(ld5)-dMay;
E5=ai(:,((round(ld5)-dMay)+1:max(ld5)));
ME=mean(E5,2);
elseif NDias==6
[row6, col]=find(NDias==6);
dJun=length(row6)/24;
ld6=row6/24;
logJun=max(ld6)-dJun;
E6=ai(:,((round(ld6)-dJun)+1:max(ld6)));
ME=mean(E6,2);
elseif NDias==7
[row7, col]=find(NDias==7);
dJul=length(row7)/24;
ld7=row7/24;
logJul=max(ld7)-dJul;
E7=ai(:,((round(ld7)-dJul)+1:max(ld7)));
ME=mean(E7,2);
elseif NDias==8
[row8, col]=find(NDias==8);
dAgo=length(row8)/24;
ld8=row8/24;
logAgo=max(ld8)-dAgo;
E8=ai(:,((round(ld8)-dAgo)+1:max(ld8)));
ME=mean(E8,2);
elseif NDias==9
[row9, col]=find(NDias==9);
dSep=length(row9)/24;
ld9=row9/24;
logSep=max(ld9)-dSep;
E9=ai(:,((round(ld9)-dSep)+1:max(ld9)));
ME=mean(E9,2);
elseif NDias==10
[row10, col]=find(NDias==10);
dOct=round(length(row10)/24);
ld10=row10/24;
logOct=max(ld10)-dOct;
E10=ai(:,(((round(logOct)-dOct)+1:max(ld10))));
ME=mean(E10,2);
elseif NDias==11
[row11, col]=find(NDias==11);
dNov=length(row11)/24;
ld11=row11/24;
logNov=max(ld11)-dNov;
E11=ai(:,(((round(logNov)-dNov)+1:max(ld11))));
ME=mean(E11,2);
%
else
[row12, col]=find(NDias==12); %
dDic=length(row12)/24; %%%%d
ld=row12/24;
logDic=max(ld)-dDic;
E12=ai(:,((max(ld)-dDic)+1:max(ld)));
ME=mean(E12,2);
end
ME_(NDias)=NDias;
plot(ME(NDias))
hold on
end

R2020a

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