# Splitting a Vector Into Groups

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T on 26 Mar 2013
I need to take in the vector A, and automatically split it up, based on a number around 60-62, without knowing how many groups I want to form.
I have a length vector:
A = [4.4708
10.6795
16.9590
23.8035
30.6478
36.2647
40.7722
43.1111
45.6896
51.9593
60.6814
66.8974
73.1607
79.9436
86.7766
92.3354
96.8187
99.1592
101.5261
107.7138
115.3084
121.4887
127.7691
134.6187
141.4633
147.0742
151.5830
153.9290
156.2800
162.4587
168.5842
174.7650
181.0298
187.8266
194.6664
200.1939
204.6659
207.0010
209.3573
215.5136]
Elements in A are in meters.
Now I have broken it up by using the following command:
v=min(A):61:max(A);
and gives the following output:
ans =
4.4708 65.4708 126.4708 187.4708
Which is close but not exact. First is it possible?
The elements that I am looking for are:
4.4708 60.6814 115.3084 168.5842
I would need to do something similiar to another vector:
1.0222
8.2938
17.3975
26.5394
37.4131
48.7097
51.4079
61.0677
67.3565
76.1626
85.4651
94.6554
105.5474
116.9902
119.6214
129.4068
133.8319
141.0227
150.2807
159.4565
170.3328
181.7071
184.2469
193.9713
197.6725
204.9526
214.0602
223.1639
233.9971
245.3746
247.9699
257.6174
260.9988
268.4480
277.6225
286.7506
297.5619
308.9268
311.5883
321.1841
328.9418
337.9682
347.0968
356.2223
367.0407
378.4586
381.1692
390.4907
With an output of:
1.0222 61.0677 133.8319 204.9526 268.4480 347.0968
But using the command I mentioned would give:
v =
Columns 1 through 6
1.0222 62.0222 123.0222 184.0222 245.0222 306.0222
Column 7
367.0222

Azzi Abdelmalek on 26 Mar 2013
Edited: Azzi Abdelmalek on 26 Mar 2013
v=min(A):61:max(A);
for k=1:numel(v)
[~,idx]=min(abs(A-v(k)));
out(k)=A(idx)
end
##### 3 CommentsShow 1 older commentHide 1 older comment
Azzi Abdelmalek on 26 Mar 2013
Based on what you will choose 51.9593?
Image Analyst on 26 Mar 2013
That was the question I had. it's not clear where he stops (it's not the max of A) and how he comes up with the step size (for example either 61 as in the first example, or 56.2106 which is 60.681-4.4708 that he wants in his second example).

Image Analyst on 26 Mar 2013
Edited: Image Analyst on 26 Mar 2013
It's not clear what you want to do but I think linspace() might be what you are looking for. You give it a min value and a max value, and a number of elements in the output array that you want and it builds it for you.
>>out = linspace(4.4708, 168.5842, 4)
out =
4.4708 59.1752666666667 113.879733333333 168.5842
T on 26 Mar 2013
Sorry. I need to take in the vector A, and automatically split it up without knowing how many groups I want to form.
linspace(4.4708, 168.5842, 4) Assumes that I know how many groups I want to split in which I cannot do.
v=min(A):61:max(A); does that but does not give the exact numbers.
Image Analyst on 26 Mar 2013
It seems that Azzi figured out what you want and solved your problem because you marked it as Accepted.