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time series with time lags

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YH
YH on 22 Sep 2020
Answered: Ameer Hamza on 22 Sep 2020
Hallo every one,
I have an array called sl(24000*1) which represents daily sea level measurements.
I have another array idx(34*1) represents the indexes of the annual maximum of a river discharg near the above mentioned gauge station
now I have to make a new time series of sea levels corresponding to the annual maximum of the river discharge time series
with time lags (-3 to +3) days, that means for each idx, i should find the coressponding value in sl with a range of -3 to +3 days.
for i = 1: size(idx,1)
out = sl(idx(i)-3:idx(i)+3);
end
this gives me only one value with its time lags
can some one tell me where exactly I am doing wrong?
Thanks in Advance!

  1 Comment

Khaled Hamed
Khaled Hamed on 22 Sep 2020
out(i,:) = sl(idx(i)-3:idx(i)+3)';

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Accepted Answer

Ameer Hamza
Ameer Hamza on 22 Sep 2020
This will create a single vector with all the required values
idx_all = arrayfun(@(x) {x-3:x+3}, idx);
out = sl([idx_all{:}])

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